They are both the same because anything times 0 equal 0 and 0+0 equals 0.
Answer:
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(You only need to give one solution)
Step-by-step explanation:
We have the following equation

First, we need to foil out the parenthesis

Now we can combine the like terms

Now, we need to factor this equation.
To factor this, we need to find a set of numbers that add together to get -3 and multiply to give us -4.
The pair of numbers that would do this would be 1 and -4.
This means that our factored form would be

As the first binomial is a difference of squares, it can be factored futher into
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Now, we can get our solutions.
The first binomial will produce two complex (Not real) solutions.


So our solutions to this equation are
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Answer:
4 : 3
Step-by-step explanation:
QRS to VUT


Answer:
4x-9.
Step-by-step explanation:
-3x - 8 + 7x - 1
7x -3x=4x.
-8 -1= - 9.
4x-9