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erik [133]
3 years ago
5

Which set of numbers gives the correct possible values of l for n = 2

Chemistry
2 answers:
Paha777 [63]3 years ago
3 0
HEY THERE!!

For a given principal quantum number or n, the corresponding angular quantum number or l is equivalent to a range between 0 and (n-1) .

This means that the angular quantum number for a principal quantum number of 2 is equivalent to:

l = 0 -> (n-1) = 0 -> (2-1) = 0 -> 1

So the answer is 0, 1

HOPE IT HELPED YOU.
lina2011 [118]3 years ago
3 0

Answer:

The possible values are l={0,1}

Explanation:

Hi,the possible values that the Azimuthal number (l) are given by the value of the Principal quantum number (n) of the atomic level you are in:

l=[0;n-1]

In this case:

For n=2 \longrightarrow n-1=2-1=1   so l values will be 0 and 1

This different values  the Azimuthal numbar can have, <u>determine the different types of sublevels that atomic level has. </u>

For example:

  • l=0 is sublevel <em>s</em>
  • l=1 is sublevel <em>p</em>
  • l=2 is sublevel <em>d</em>
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Monica [59]

Answer:

Option C :

a chemical formula that shows the relative number of each type of atom in a molecule, using the smallest possible ratio

Explanation:

Empirical Formula:

Empirical formula is the simplest ration of atoms in the molecule but not all numbers of atoms in a compound.

So,

Tha ration of the molecular formula should be divided by whole number to get the simplest ratio of molecule

For Example

      C₂H₆O₂ Consist of  Carbon (C), Hydrogen (H), and Oxygen (O)

Now

Look at the ratio of these three atoms in the compound

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Divide the ratio by two to get simplest ratio

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So for the empirical formula the simplest ratio of carbon to hydrogen to oxygen is 1:3:1

So the empirical formula will be

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So, Option C is correct :

a chemical formula that shows the relative number of each type of atom in a molecule, using the smallest possible ratio

6 0
3 years ago
A sulfuric acid solution containing 571.3 g of h2so4 per liter of aqueous solution has a density of 1.329 g/cm3. Part a calculat
loris [4]

Mass percentage of a solution is the amount of solute present in 100 g of the solution.

Given data:

Mass of solute H2SO4 = 571.3 g

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Given:

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2.00 liters of solution

 

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pH = 6.25 + log 0.3045/ 0.3035 = 6.25 is the ph buffer prepared.

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Answer:

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