All categories

3 years ago

Where does energy in an ecosystem come from?

Chemistry

2 answers:

Novay_Z [31]3 years ago

4 0

Answer:

Energy in an ecosystem comes from the Sun.

Explanation:

It is a major source of energy for organisms, plants and the whole ecosystem basically.

Mashcka [7]3 years ago

4 0

Answer:

Most of the energy in an ecosystem comes from the sun, most producers such as plants, algae, etc. use the energy from the sun to create organic matter from carbon dioxide and water.

You might be interested in

A compound differs from a mixture in that a compound always has a?

MissTica

1 is the answer because I studied science it's right number 1 is the correct one homogeneous composition

3 0

3 years ago

Read 2 more answers

In reality, energy conversion from burning fuel is never 100% efficient. Significant loss of energy due to heating occurs. If th

algol [13]

Answer:

Electrical energy = 130000000 J and Heat energy = 520000000 J

Explanation:

Multiply the amount of joules from the last question (650000000) by .20 and .80. (Which are the percentages)

6 0

2 years ago

What is the Nobel gas notation for selenium

seraphim [82]

Answer:

Se =[Ar] 3d¹⁰ 4s² 4p⁴

Explanation:

The noble gas notation is used for the shortest electronic configuration of other periodic table elements.

For example:

The atomic number of Argon is 18, and its electronic configuration is,

Ar₁₈ = 1s² 2s² 2p⁶ 3s² 3p⁶

The atomic number of selenium is 34, its electronic configuration is,

Se₃₄ = 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰ 4s² 4p⁴

By using the noble gas notation, electronic configuration of selenium can be written is shortest form.

Se =[Ar] 3d¹⁰ 4s² 4p⁴

This electronic configuration is also called abbreviated electronic configuration.

5 0

3 years ago

if you pour out some of the water in a bucket,does the density of the remaining water change? explain.

Aleksandr [31]

The density does not change because it is still the same liquid as before

5 0

3 years ago

Read 2 more answers

Combine the two half-reactions that give the spontaneous cell reaction with the smallest E∘. Fe2+(aq)+2e−→Fe(s) E∘=−0.45V I2(s)+

Iteru [2.4K]

Answer: The spontaneous cell reaction having smallest $E^o$ is $I_2+Cu\rightarrow Cu^{2+}+2I^-$

Explanation:

We are given:

$E^o_{(Fe^{2+}/Fe)}=-0.45V\\E^o_{(I_2/I^-)}=0.54V\\E^o_{(Cu^{2+}/Cu)}=0.34V$

The substance having highest positive $E^o$ potential will always get reduced and will undergo reduction reaction. Here, iodine will always undergo reduction reaction, then copper and then iron.

The equation used to calculate electrode potential of the cell is:

$E^o_{cell}=E^o_{oxidation}+E^o_{reduction}$

The combination of the cell reactions follows:

Case 1:

Here, iodine is getting reduced and iron is getting oxidized.

The cell equation follows:

$I_2(s)+Fe(s)\rightarrow Fe^{2+}(aq.)+2I^-(aq.)$

Oxidation half reaction: $Fe(s)\rightarrow Fe^{2+}(aq.)+2e^-$ $E^o_{oxidation}=0.45V$

Reduction half reaction: $I_2(s)+2e^-\rightarrow 2I_-(aq.)$ $E^o_{reduction}=0.54V$

$E^o_{cell}=0.45+0.54=0.99V$

Thus, this cell will not give the spontaneous cell reaction with smallest $E^o_{cell}$

Case 2:

Here, iodine is getting reduced and copper is getting oxidized.

The cell equation follows:

$I_2(s)+Cu(s)\rightarrow Cu^{2+}(aq.)+2I^-(aq.)$

Oxidation half reaction: $Cu(s)\rightarrow Cu^{2+}(aq.)+2e^-$ $E^o_{oxidation}=-0.34V$

Reduction half reaction: $I_2(s)+2e^-\rightarrow 2I_-(aq.)$ $E^o_{reduction}=0.54V$

$E^o_{cell}=-0.34+0.54=0.20V$

Thus, this cell will give the spontaneous cell reaction with smallest $E^o_{cell}$

Case 3:

Here, copper is getting reduced and iron is getting oxidized.

The cell equation follows:

$Cu^{2+}(aq.)+Fe(s)\rightarrow Fe^{2+}(aq.)+Cu(s)$

Oxidation half reaction: $Fe(s)\rightarrow Fe^{2+}(aq.)+2e^-$ $E^o_{oxidation}=0.45V$

Reduction half reaction: $Cu^{2+}(aq.)+2e^-\rightarrow Cu(s)$ $E^o_{reduction}=0.34V$

$E^o_{cell}=0.45+0.34=0.79V$

Thus, this cell will not give the spontaneous cell reaction with smallest $E^o_{cell}$

Hence, the spontaneous cell reaction having smallest $E^o$ is $I_2+Cu\rightarrow Cu^{2+}+2I^-$

7 0

3 years ago