3 years ago

If you have an atom or copper, an ion of copper and an isotope of copper, what

1 answer:

3 0

PLEASE HELP!! PLEASE??

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ololo11 [35]

Third choice because the others make no sense

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3 years ago

KiRa [710]

The answer is *B. Prey*

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3 years ago

Flauer [41]

Answer : The amount of formaldehyde permissible are, $5.4\times 10^{-6}g$

Explanation : Given,

Density of air = $1.2kg/m^3=1.2g/L$ $(1kg/m^3=1g/L)$

First we have to calculate the mass of air.

$\text{Mass of air}=\text{Density of air}\times \text{Volume of air}$

$\text{Mass of air}=1.2g/L\times 6.0L$

$\text{Mass of air}=7.2g$

Now we have to calculate the amount of formaldehyde.

Permissible exposure level of formaldehyde = 0.75 ppm = $\frac{0.75g\text{ of formaldehyde}}{10^6g\text{ of air}}$

Amount of formaldehyde in 7.2 g of formaldehyde = $7.2g\times \frac{0.75g\text{ of formaldehyde}}{10^6g\text{ of air}}$

Amount of formaldehyde in 7.2 g of formaldehyde = $5.4\times 10^{-6}g$

Thus, the amount of formaldehyde permissible are, $5.4\times 10^{-6}g$

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3 years ago

lakkis [162]

I see you have access to the internet. Google 'Kelvin to C', and input 251. You'll get -22.15.

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3 years ago

bonufazy [111]

I am confused on what your question is. Any more details?

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3 years ago