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3 years ago

8

What is the Electronic geometry and the Molecular geometry for CH3NH2?

1 answer:

tangare [24]3 years ago

5 0

From Lewis structure it is shown that the Nitrogen atom also contains a lone pair of electron. So, According to Valence Shell Electron Pair Repulsion (VSEPR) Theory, those central atoms which have four electron pairs and all of them are bonding electron pairs gives Tetrahedral Geometry.

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Radio waves, which travel at the speed of light, are used to communicate with satellites in space. If a message from flight cont

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Answer:

Is this on edgenuity or some type of virtual school Lmk and then i could help !

Explanation:

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3 years ago

What type of substance is magnesium carbonate?

tresset_1 [31]

Magnesium salt is the type of substance

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3 years ago

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Por que esmas dificil erradicar la mineria ilegal q la mineria de grande empresas

kari74 [83]

Answer:

I Don't Understand

Explanation:

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4 years ago

A chemist added an excess of sodium sulfate to a solution of a soluble barium compound to precipitate all of the barium ion as b

AnnyKZ [126]

Answer : The mass percentage of barium in the compound is, 53.8 %

Explanation : Given,

Mass of barium compound = 441 mg

Mass of barium sulfate = 403 mg = 0.403 g (1 mg = 0.001 g)

The balanced chemical reaction will be:

$Ba^{2+}(aq)+Na_2SO_4(aq)\rightarrow BaSO_4(s)+2Na^+(aq)$

First we have to calculate the moles of $BaSO_4$

$\text{Moles of }BaSO_4=\frac{\text{Mass of }BaSO_4}{\text{Molar mass of }BaSO_4}$

Molar mass of $BaSO_4$ = 233.38 g/mole

$\text{Moles of }BaSO_4=\frac{0.403g}{233.38g/mole}=0.001727mole$

Now we have to calculate the moles of barium ion.

From the balanced chemical reaction, we conclude that

As, 1 mole of barium sulfate produced from 1 mole of barium ion

So, 0.001727 mole of barium sulfate produced from 0.001727 mole of barium ion

Now we have to calculate the mass of barium ion.

$\text{ Mass of }Ba^{2+}=\text{ Moles of }Ba^{2+}\times \text{ Molar mass of }Ba^{2+}$

Molar mass of barium = 137.3 g/mol

$\text{ Mass of }Ba^{2+}=(0.001727moles)\times (137.3g/mole)=0.2371g$

Now we convert the mass of barium ion from gram to mg.

Conversion used : (1 g = 1000 mg)

Mass of barium ion = 0.2371 g = 237.1 mg

Now we have to calculate the mass percentage of barium in the compound.

Mass percent of barium = $\frac{237.1mg}{441mg}\times 100=53.8\%$

Thus, the mass percentage of barium in the compound is, 53.8 %

8 0

4 years ago

BaCl2(H2O)2 type of reaction

amid [387]

Answer:

2HCl + Ba(OH)2 = BaCl2 + 2H2O

Explanation:

3 0

4 years ago