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ahrayia [7]
2 years ago
8

All elements have a AHf, of ___

Chemistry
1 answer:
stellarik [79]2 years ago
7 0

All elements have a AHf, of <u>0</u>

kJ/mole at standard temperature and pressure.

<h3>What is an element?</h3>

An element can be defined as a substance which cannot be split into two or more simpler forms by an ordinary chemical process

Below are the list of the first twenty elements:

  • Hydrogen
  • Helium
  • Lithium
  • Berylium
  • Boron
  • Carbon
  • Nitrogen
  • Oxygen
  • Fluorine
  • Neon
  • Sodium
  • Magnesium
  • Aluminum
  • Silicon
  • Phosphorus
  • Sulphur
  • Chlorine
  • Argon
  • Potassium
  • Calcium

So therefore, all elements have a AHf, of <u>0</u>

kJ/mole at standard temperature and pressure.

Learn more about elements:

brainly.com/question/11829854

#SPJ1

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Answer : The value of K_{goal} for the final reaction is, 1.238\times 10^{-7}

Explanation :

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(1) 2CO_2(g)+2H_2O(l)\rightleftharpoons CH_3COOH(l)+2O_2 K_1=5.40\times 10^{-16}

(2) 2H_2(g)+O_2(g)\rightleftharpoons 2H_2O(l) K_2=1.06\times 10^{10}

(3) CH_3COOH(l)\rightleftharpoons 2C(s)+O_2(g) K_3=2.68\times 10^{-9}

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CO_2(g)\rightleftharpoons C(s)+O_2(g) K_{goal}=?

Now we have to calculate the value of K_{goal} for the final reaction.

First half the equation 1, 2 and 3 that means we are taking square root of equilibrium constant and then add all the equation 1, 2 and 3 that means we are multiplying all the equilibrium constant, we get the final equilibrium reaction and the expression of final equilibrium constant is:

K_{goal}=\sqrt{K_1\times K_2\times K_3}

Now put all the given values in this expression, we get :

K_{goal}=\sqrt{(5.40\times 10^{-16})\times (1.06\times 10^{10})\times (2.68\times 10^{-9})}

K_{goal}=1.238\times 10^{-7}

Therefore, the value of K_{goal} for the final reaction is, 1.238\times 10^{-7}

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<h2>Let us complete it :</h2>

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