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anygoal [31]
3 years ago
12

Oh noes! I’ve stained myself with what looks like marker. What do you think is the best way to remove this stain?

Chemistry
2 answers:
BigorU [14]3 years ago
4 0

Hello  <u>Bobby792003</u>

The best way to get rid of a marker stain on your skin is <u><em>rubbing alcohol.</em></u>

:)

Sonbull [250]3 years ago
3 0
Try warm water& soap if u haven’t already,if that doesn’t work try rubbing alcohol
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Round 0.0011675cg to four significant figures
atroni [7]

Answer:

answer is 0.001168 is correct

8 0
2 years ago
Brenda rode a skateboard 95 meters west. It took her 20 seconds. What was
Artemon [7]

Answer:

D. 4.75 m/s west

Explanation:

You can immediately get the answer once you know the formula for<em> velocity.</em>

  • The formula for velocity is: Velocity (V) = \frac{distance (d)}{time (t)}

The distance is 95 meters while the time is 20 seconds. All you have to do is to divide <u>95 meters by 20 seconds</u>.

Let's solve:

  • V = \frac{d}{t}
  • V = \frac{95 meters}{20 seconds}
  • V = 4.75 meters per second

Since Brenda is going west with her her skateboard, then you have to add <em>west </em>as her direction.

Brenda's velocity is 4.75 m/s west.

5 0
3 years ago
Color is an example of
Nuetrik [128]

Answer:

a physical property

Explanation:

Color does not change state.

- Hope that helped! Please let me know if you need further explanation.

3 0
2 years ago
100.0 g of 4.0°C water is heated until its temperature is 37.0°C. If the specific heat of water is 4.184 J/g°C, calculate the am
Lady bird [3.3K]

Answer:

13.8072 kj

Explanation:

Given data:

Mass of water = 100.0 g

Initial temperature = 4.0 °C

Final temperature = 37.0°C

Specific heat capacity = 4.184 j/g.°C

Heat absorbed = ?

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 37.0°C -  4.0 °C

ΔT = 33.0°C

Q = 100.0 g ×4.184 j/g.°C × 33.0°C

Q = 13807.2 j

Joule to KJ:

13807.2 j  × 1kj  /1000 j

13.8072 kj

5 0
3 years ago
Which statement is incorrect regarding the reaction of benzene with an electrophile? View Available Hint(s) A) The carbocation i
Leno4ka [110]

Answer:

The carbocation intermediate reacts with a nucleophile to form the addition product.

Explanation:

The reaction of benzene with an electrophile is an electrophillic substitution reaction. Here the electrophile replaces hydrogen. There is no formation of carbocation as intermediate in the reaction. Infact there is transition state where the electorphile attacks on benzene ring and at the same time the hydrogen gets removed from the benzene. So a transition carbocation is formed.

The general mechanism is shown in the figure.

i) Attack of the electrophile on the benzene (which is the nucleophile)

ii) The carbocation intermediate loses a proton from the carbon bonded to the electrophile.

iii) the carbocation formation is the rate determining step.

iv) There is no formation of addition product.

Thus the wrong statement is

The carbocation intermediate reacts with a nucleophile to form the addition product.

3 0
3 years ago
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