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zhenek [66]
3 years ago
9

What is the equation for elastic potential energy?

Physics
2 answers:
drek231 [11]3 years ago
6 0

Answer: HOPE THIS HELPED YOU! :D      ;P

Elastic potential energy = force x distance of displacement.

Explanation:

docker41 [41]3 years ago
4 0

Answer:

force times distance of displacement

Explanation:

Elastic potential energy is equal to the force times the distance of movement. Elastic potential energy = force x distance of displacement. Because the force is = spring constant x displacement, then the Elastic potential energy = spring constant x displacement squared.

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Two 2.0 cm by 2.0 cm metal electrodes are spaced 1.0 mm apart and connected by wires of the terminals of a 9.0 V battery.
ale4655 [162]

Answer:

Explanation:

Area of electrodes, A = 2 cm x 2 cm = 4 cm²

Separation between electrodes, d = 1 mm

Voltage, V = 9 V

(a)

Let C is the capacitance between the electrodes

C = \frac{\epsilon _{0}A}{d}

C = \frac{8.854\times 10^{-12}\times 4\times 10^{-4}}{1\times 10^{-3}}

C = 3.54 x 10^-12 F

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q = C x V

q = 3.54 x 10^-12 x 9 = 3.2 x 10^-11 C

(b)

As, the battery is disconnected the charge on the electrodes remains same.

(c)

As the battery is connected the voltage is same.

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3 years ago
Which of the advantages to social media as a new media could also be viewed as a disadvantage
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You have a small piece of iron at 75 °C and place it into a large container of water at 25 °C. Which of these best explains what
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You know your mass is 62 kg but when you stand on a bathroom scale in an elevator it says your mass is 77 kg what is the acceler
lbvjy [14]
In a stationary situation, the weight of person is
W=mg=(62 kg)(9.81 m/s^2) = 608.2 N
This is the weight "felt" by the scale, which is basically the normal reaction applied by the scale on the person, and which uses the value of g (9.81) as reference to convert the weight (602.8 N) into a mass (62 kg).

When the person is in the elevator, the scale says 77 kg. The scale is still using the same value of conversion (9.81), so the apparent weight "felt" by the scale is
W' = m'g=(77 kg)(9.81 m/s^2)=755.4 N
This is the normal reaction applied by the scale on the person, and which is directed upward. Besides this force, there is still the weight W of the person, acting downward. So, if we use Newton's second law:
\sum F = ma
W-W'=ma
where a is the acceleration of the elevator. If we solve for a, we find
a= \frac{W-W'}{m}= \frac{608.2N-755.4N}{62 kg}=-2.37 m/s^2
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3 years ago
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