The force applied to the spring is the weight of the object that compresses it, so it is equal to:

Because of this force, the spring compresses by

. Using Hook's law,

,
since we know the intensity of the force (the weight W) and the compression of the spring, x, we can find k, the spring constant:
Answer:
Knowing we only have one load applied in just one direction we have to use the Hooke's law for one dimension
ex = бx/E
бx = Fx/A = Fx/π
Using both equation and solving for the modulus of elasticity E
E = бx/ex = Fx / π
ex
E = 
Apply the Hooke's law for either y or z direction (circle will change in every direction) we can find the change in radius
ey =
(бy - v (бx + бz)) =
бx
=
= 
Finally
ey = Δr / r
Δr = ey * r = 10 * 
Δd = 2Δr = 
Explanation:
V=IR
The more V, the more I
The correct answer for this is A. <span>Accompany her to talk with your parents or another trusted adult to ask for help
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The MA is 6! Hope This Helps!