Answer:
a=1.024m/s
t=15.62s
Explanation:
A body that moves with constant acceleration means that it moves in "a uniformly accelerated movement", which means that if the velocity is plotted with respect to time we will find a line and its slope will be the value of the acceleration, it determines how much it changes the speed with respect to time.
When performing a mathematical demonstration, it is found that the equations that define this movement are as follows.
Vf=Vo+a.t (1)
{Vf^{2}-Vo^2}/{2.a} =X (2)
X=Xo+ VoT+0.5at^{2} (3)
X=(Vf+Vo)T/2 (4)
Where
Vf = final speed
Vo = Initial speed
T = time
A = acceleration
X = displacement
In conclusion to solve any problem related to a body that moves with constant acceleration we use the 4 above equations and use algebra to solve
for this problem
Vf=16m/s
Vo=0m/s, the cart starts from the rest
X=125m
we can use the ecuation number tow to calculate the acceleration
{Vf^{2}-Vo^2}/{2.a} =X
{Vf^{2}-Vo^2}/{2.x} =a
{16^{2}-0^2}/{2(125)} =a
a=1.024m/s
to calculate the time we can use the ecuation number 1
Vf=Vo+a.t
t=(Vf-Vo)/a
t=(16-0)/1.024
t=15.62s
The answer is B- 384,400
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Answer:
I hope this helps
Explanation:
i had to submit just to get the answer,Have a great day!!!
To solve this problem it is necessary to apply the concepts related to Young's Module and its respective mathematical and modular definitions. In other words, Young's Module can be expressed as
Where,
F = Force/Weight
A = Area
= Compression
= Original Length
According to the values given we have to
Replacing this values at our previous equation we have,
Therefore the Weight of the object is 3.82kN
