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sesenic [268]
3 years ago
11

I WILL GIVE BRAINLIEST TO WHOEVER IS CORRECT.

Physics
2 answers:
Tems11 [23]3 years ago
6 0
Ultraviolet light with a wavelength shorter than visible light and a higher radiant energy than visible light.

The shorter the wavelength, the higher the frequency and energy.
Reptile [31]3 years ago
4 0
Ultraviolent light has shorter wave lenght but higher frequency
You might be interested in
Half life of a given sample of radium is 22 years the sample will reduce to 25% of its original value after
makkiz [27]

Answer:

44 years

Explanation:

Use half life equation:

A = A₀ (½)^(t / T)

where A is the final amount,

A₀ is the initial amount,

t is time,

and T is the half life.

0.25 A₀ = A₀ (½)^(t / 22)

0.25 = (½)^(t / 22)

t / 22 = 2

t = 44

3 0
3 years ago
If a tree falls in the middle of the woods and nobody is around to hear it, does it make a sound?
solong [7]
Yes, everything falling will make a sound unless it is air.
7 0
3 years ago
Read 2 more answers
How does a pedometer help people reach their fitness goals?
Greeley [361]

Answer:

Pedometers are designed to detect vertical movement at the hip and so measure the number of steps and provide an estimate of distance walked. They cannot provide information on the temporal pattern of physical activity or the time spent in different activity at different intensity.

5 0
3 years ago
Suman with a mass of 45kg climbs in 3m heigh ladder in 10 seconds. Calculate her power. Plz help me​
attashe74 [19]

Answer:

work done=fdcosø

f=mg=450N

d=+3m

ø=180

450×3×cos(180°) power=work done/

time taken

1350×-1 p=135watts

7 0
3 years ago
A boxer punches a sheet of paper in midair and brings it from rest up to a speed of 30 m/s in 0.060 s .
zimovet [89]

Answer:

Force exerted, F = 1.5 N

Explanation:

It is given that, a boxer punches a sheet of paper in midair and brings it from rest up to a speed of 30 m/s in 0.060 s.

i.e. u = 0

v = 30 m/s

Time taken, t = 0.06 s

Mass of the paper, m = 0.003 kg

We need to find the force the boxer exert on it. The force can be calculated using second law of motion as :

F=m\times a

F=m\times (\dfrac{v-u}{t})

F=0.003\times (\dfrac{30}{0.06})

F = 1.5 N

So, the force the boxer exert on the paper is 1.5 N. Hence, this is the required solution.

6 0
3 years ago
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