C and A the first one is a bit weird but thats what i got and you cant even see it that good
Right Atrium, Left Atrium, Pulmonary Trunk, Left Pulmonary Artery, Right Pulmonary Artery, Right Ventricle, Left Ventricle, Inferior Vena Cava, Superior Vena Cava, Acending Aorta, Aortic Arch, Apex, Left Pulmonary Veins, Right Pulmonary Veins, Brachiocepalic Artery, Ligamentum Arteriosum, Auricle, Left Common Carotoid Artery, Left Subclavian Artery, Anterior Cardiac Vein, Anterior Interventricular Artery, Left Coronary Artery (in coronary sulcus, left coronary groove), Great Cardiac Vein, Marginal Artery, Small Cardiac Vein, Right Coronary Artery (in coronary sulcus,Right coronary groove)
Here hope this helps:)
-- We know that the y-component of acceleration is the derivative of the
y-component of velocity.
-- We know that the y-component of velocity is the derivative of the
y-component of position.
-- We're given the y-component of position as a function of time.
So, finding the velocity and acceleration is simply a matter of differentiating
the position function ... twice.
Now, the position function may look big and ugly in the picture. But with the
exception of 't' , everything else in the formula is constants, so we don't even
need any fancy processes of differentiation. The toughest part of this is going
to be trying to write it out, given the text-formatting capabilities of the wonderful
envelope-pushing website we're working on here.
From the picture . . . . . y (t) = (1/2) (a₀ - g) t² - (a₀ / 30t₀⁴ ) t⁶
First derivative . . . y' (t) = (a₀ - g) t - 6 (a₀ / 30t₀⁴ ) t⁵ = (a₀ - g) t - (a₀ / 5t₀⁴ ) t⁵
There's your velocity . . . /\ .
Second derivative . . . y'' (t) = (a₀ - g) - 5 (a₀ / 5t₀⁴ ) t⁴ = (a₀ - g) - (a₀ /t₀⁴ ) t⁴
and there's your acceleration . . . /\ .
That's the one you're supposed to graph.
a₀ is the acceleration due to the model rocket engine thrust
combined with the mass of the model rocket
'g' is the acceleration of gravity ... 9.8 m/s² or 32.2 ft/sec²
t₀ is how long the model rocket engine burns
Pick, or look up, some reasonable figures for a₀ and t₀
and you're in business.
The big name in model rocketry is Estes. Their website will give you
all the real numbers for thrust and burn-time of their engines, if you
want to follow it that far.
Answer:
yes for both.
Explanation:
according to Newton's first law an object in motion will stay in motion until acted on by an outside force and an object at rest will stay at rest until acted on by an outside force. this means that an object that is moving will stay moving in the direction that it's moving and at the same speed unless there's an outside force acting on it and it will keep in motion until there is an outside force acting on it.
