Answer:
The ball will fall back and land to Elle's hands.
Explanation:
The bus move in a straight line with constant velocity means that there is no change of direction and no acceleration. Inertia can change the direction of the ball and acceleration can change its velocity. Since these two factors is not present in this scenario, the ball only has vertical movement. Thus the ball will land where it was thrown, in Elle's hands.
Answer:
a
![l_o =52 \ m](https://tex.z-dn.net/?f=l_o%20%20%3D52%20%5C%20%20m)
b
![l = 37.13 \ LY](https://tex.z-dn.net/?f=l%20%3D%2037.13%20%5C%20LY)
Explanation:
From the question we are told that
The speed of the spaceship is ![v = 0.800c](https://tex.z-dn.net/?f=v%20%20%3D%20%200.800c)
Here c is the speed of light with value ![c = 3.0*10^{8} \ m/s](https://tex.z-dn.net/?f=c%20%3D%20%203.0%2A10%5E%7B8%7D%20%5C%20m%2Fs)
The length is ![l = 31.2 \ m](https://tex.z-dn.net/?f=l%20%3D%2031.2%20%5C%20%20m)
The distance of the star for earth is ![d = 145 \ light \ years](https://tex.z-dn.net/?f=d%20%3D%20145%20%5C%20%20light%20%5C%20%20years)
The speed is ![v_s = 2.90 *10^{8}](https://tex.z-dn.net/?f=v_s%20%3D%202.90%20%2A10%5E%7B8%7D)
Generally the from the length contraction equation we have that
![l = l_o \sqrt{1 -[\frac{v}{c } ]}](https://tex.z-dn.net/?f=l%20%20%3D%20%20l_o%20%20%5Csqrt%7B1%20-%5B%5Cfrac%7Bv%7D%7Bc%20%7D%20%5D%7D)
Now the when at rest the length is ![l_o](https://tex.z-dn.net/?f=l_o)
So
![l_o =\frac{l}{\sqrt{ 1 - \frac{v^2}{c^2 } } }](https://tex.z-dn.net/?f=l_o%20%3D%5Cfrac%7Bl%7D%7B%5Csqrt%7B%201%20-%20%5Cfrac%7Bv%5E2%7D%7Bc%5E2%20%7D%20%7D%20%7D)
![l_o =\frac{ 31.2 }{ \sqrt{1 - \frac{(0.800c ) ^2}{c^2} } }](https://tex.z-dn.net/?f=l_o%20%3D%5Cfrac%7B%2031.2%20%7D%7B%20%5Csqrt%7B1%20-%20%5Cfrac%7B%280.800c%20%29%20%5E2%7D%7Bc%5E2%7D%20%7D%20%7D)
![l_o=52 \ m](https://tex.z-dn.net/?f=l_o%3D52%20%5C%20%20m)
Considering b
Applying above equation
![l =l_o \sqrt{1 - [\frac{v}{c } ]}](https://tex.z-dn.net/?f=l%20%20%3Dl_o%20%5Csqrt%7B1%20-%20%20%5B%5Cfrac%7Bv%7D%7Bc%20%7D%20%5D%7D)
Here ![l_o =145 \ LY(light \ years )](https://tex.z-dn.net/?f=l_o%20%20%3D145%20%5C%20%20LY%28light%20%5C%20years%20%29)
So
![l=145 * \sqrt{1 - \frac{v_s^2}{c^2 } }](https://tex.z-dn.net/?f=l%3D145%20%2A%20%20%5Csqrt%7B1%20-%20%20%5Cfrac%7Bv_s%5E2%7D%7Bc%5E2%20%7D%20%7D)
![l =145 * \sqrt{ 1 - \frac{2.9 *10^{8}}{3.0*10^{8}} }](https://tex.z-dn.net/?f=l%20%3D145%20%2A%20%20%5Csqrt%7B%201%20-%20%5Cfrac%7B2.9%20%2A10%5E%7B8%7D%7D%7B3.0%2A10%5E%7B8%7D%7D%20%7D)
![l = 37.13 \ LY](https://tex.z-dn.net/?f=l%20%3D%2037.13%20%5C%20LY)
Answer:
0.173 m.
Explanation:
The fundamental frequency of a closed pipe is given as
fc = v/4l .................. Equation 1
Where fc = fundamental frequency of a closed pipe, v = speed of sound l = length of the pipe.
Making l the subject of the equation,
l = v/4fc ................ Equation 2
also
v = 331.5×0.6T ................. Equation 3
Where T = temperature in °C, T = 18.0 °c
Substitute into equation 3
v = 331.5+0.6(18)
v = 331.5+10.8
v = 342.3 m/s.
Also given: fc = 494 Hz,
Substitute into equation 2
l = 342.3/(4×494)
l = 342.3/1976
l =0.173 m.
Hence the length of the organ pipe = 0.173 m.
Answer:
induced EMF = 240 V
and by the lenz's law direction of induced EMF is opposite to the applied EMF
Explanation:
given data
inductance = 8 mH
resistance = 5 Ω
current = 4.0 A
time t = 0
current grow = 4.0 A to 10.0 A
to find out
value and the direction of the induced EMF
solution
we get here induced EMF of induction is express as
E = - L
...................1
so E = - L ![\frac{I2 - I1}{dt}](https://tex.z-dn.net/?f=%5Cfrac%7BI2%20-%20I1%7D%7Bdt%7D)
put here value we get
E = - 8 ×
![\frac{10 - 4}{0.2*10^{-3}}](https://tex.z-dn.net/?f=%5Cfrac%7B10%20-%204%7D%7B0.2%2A10%5E%7B-3%7D%7D)
E = -40 × 6
E = -240
take magnitude
induced EMF = 240 V
and by the lenz's law we get direction of induced EMF is opposite to the applied EMF