Just took the test and the answer is <span>C. 1,314,718.
</span>
5m
Explanation:
Given parameters:
Weight of object = 50N
Work done in lifting object = 250J
Unknown:
Vertical height = ?
Solution:
The work done on an object is the force applied to lift a body in a specific direction.
Work done = force x distance
Weight is a force in the presence of gravity;
Work done = weight x height of lifting
Height of lifting = ![\frac{work done }{weight}](https://tex.z-dn.net/?f=%5Cfrac%7Bwork%20done%20%7D%7Bweight%7D)
Height of lifting =
= 5m
The vertical height through which the object was lifted is 5m
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Answer:
<h2>1.17 m/s²</h2>
Explanation:
The acceleration of an object given it's mass and the force acting on it can be found by using the formula
![a = \frac{f}{m} \\](https://tex.z-dn.net/?f=a%20%3D%20%20%5Cfrac%7Bf%7D%7Bm%7D%20%20%5C%5C%20)
f is the force
m is the mass
From the question we have
![a = \frac{700}{600} = \frac{7}{6} \\ = 1.1666666...](https://tex.z-dn.net/?f=a%20%3D%20%20%5Cfrac%7B700%7D%7B600%7D%20%20%3D%20%20%5Cfrac%7B7%7D%7B6%7D%20%20%5C%5C%20%20%3D%201.1666666...)
We have the final answer as
<h3>1.17 m/s²</h3>
Hope this helps you
Answer:
Explanation:
Newton's first law of motion states that an object in motion stays in motion. The orange is moving and then the tray stops making the orange move forward because of inertia.