Which is an equation of a circle with center (2, -1) that passes through the point (3, 4)?

1 answer:

5 0

Let A be (2,-1) & B be (3,4). The radius of the circle is AB. Let's calculate it

AB =√{(3-2)²+(4+1)²] = √26

Now the standard form of the equation of a circle:

(x-h)²+(y-k)² = R²

(x-2)²+(y-1)² = 26

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