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3 years ago

10

In a diagram of a landscape plan, the scale is 1 cm = 10 ft. in the diagram, the trees are 4.3 cm apart. How far apart should th

e actual trees be planted?
43 ft

430 ft

1.3 ft

0.43 ft

1 answer:

Vaselesa [24]3 years ago

3 0

The actual trees should be planted 43 ft apart

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4 years ago

Solve each triangle using the information provided. If necessary, round to the<br> nearest tenth.

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Answer:

1) B = 66.5° c = 10.9

Step-by-step explanation:

I will do question one as an example. In general, for these questions you want to use the appropriate trigonometric ratios to solve for the variables and/or apply logic using rules regarding triangles. See attached image for all solving steps.

For side c, we can use Cosine of angle A for a ratio between 10 and c. When we write out the equation, we can solve for side c. So when we write it out, we get the equation:

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3 years ago

Find the cross product of <img src="https://tex.z-dn.net/?f=-%20%5Cfrac%7B3%7D%7B4%7Dv" id="TexFormula1" title="- \frac{3}{4}v"

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For any scalars $c_1,c_2$ , we have

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So

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$=\begin{bmatrix}-60\\9\\76\end{bmatrix}$

which makes

$\left(-\dfrac34\mathbf v\right)\times\left(-\dfrac12\mathbf w\right)=\dfrac38\begin{bmatrix}-60\\9\\76\end{bmatrix}=\begin{bmatrix}-\frac{45}2\\\\\frac{27}8\\\\\frac{57}2\end{bmatrix}$

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