Answer:
About 60 grams
Explanation:
The balanced equation of the reaction is given as;
2H2(g) + O2(g) → 2H2O(l)
From the equation;
2 mol of H2 reacts with 1 mol of O2
3 mol of H2 would require 3/2 mol of O2 (considering the 2:1 ratio)
The limiting reactant is H2 as it would be used up before H2. It determines the amount of product that would be formed.
2 mol of H2 produces 2 mol of H2O
3 mol of H2 would produce 3 mol of H2O (Considering the 1 : 1 ratio)
Converting moles to mass;
Mass = Molar mass * Number of moles
Mass = 18 * 3 = 54 g
The correct option is; About 60 grams
Answer : The molal freezing point depression constant of liquid X is, 
Explanation : Given,
Mass of urea (solute) = 5.90 g
Mass of liquid X (solvent) = 450 g = 0.450 kg
Molar mass of urea = 60 g/mole
Formula used :
where,
= change in freezing point
= freezing point of solution = 
= freezing point of liquid X = 
i = Van't Hoff factor = 1 (for non-electrolyte)
= Molal-freezing-point-depression constant = ?
m = molality
Now put all the given values in this formula, we get
Therefore, the molal freezing point depression constant of liquid X is,
Answer:
In numerical order left to right, they are arranged by the number of protons in the nucleus of a single atom of each element
