Answer:
32.83 grams of NH₄F can be formed from 34.6 grams of CaF₂
Explanation:
The balanced reaction is:
CaF₂ + (NH₄)₂O ⇒ 2 NH₄F + CaO
By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the following quantities participate in the reaction:
- CaF₂: 1 mole
- (NH₄)₂O: 1 mole
- NH₄F: 2 mole
- CaO: 1 mole
Being the molar mass of the compounds:
- CaF₂: 78 g/mole
- (NH₄)₂O: 52 g/mole
- NH₄F: 37 g/mole
- CaO: 56 g/mole
Then by stoichiometry, the following amounts of mass participate in the reaction:
- CaF₂: 1 mole* 78 g/mole= 78 g
- (NH₄)₂O: 1 mole* 52 g/mole= 52 g
- NH₄F: 2 mole* 37 g/mole= 74 g
- CaO: 1 mole* 56 g/mole= 56 g
You can apply the following rule of three: if 78 grams of CaF₂ form 74 grams of NH₄F by stoichiometry, 34.6 grams of CaF₂ will form how much mass of NH₄F?

mass of NH₄F= 32.83 grams
<u><em>32.83 grams of NH₄F can be formed from 34.6 grams of CaF₂</em></u>
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Half life is the time taken by a radioactive isotope to decay by half its original mass.
The original mass is 200 g
Time taken is 60 hours
Final mass is 25 g
Therefore;
Final mass = Original mass × (1/2)^n; where n is the number of half lives.
25 = 200 (1/2)^n
1/8 = (1/2)^n
n = 3
Three half lives = 60 hours
1 half lives = 20 hours
Therefore; the half life of the radioactive nucleus is 20 hours
To answer this expression we should follow the mathematical rule. The mathematical rule that we will follow is called BODMAS short for brackets, powers, divide, multiply, add, subtract. So, we will first solve the one in the brackets which is <span>(72.61 - 68.59) is equal to 4.02 then we will multiply this to 18.76 and the answer is 75.4152.</span>
1 mole = 6.22 x 10^23 molecules (Avogadro's number)
15 moles x (6.22 x 10^23) = 9.33 x 10^24 atoms