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Firlakuza [10]
2 years ago
8

In a body of water, the surface tension caused by the attraction between water molecules is strong. Which of the following is a

consequence of this property?
Chemistry
2 answers:
topjm [15]2 years ago
7 0
I think that since the attraction is strong, the water will freeze
Margaret [11]2 years ago
4 0
<span>When water freezes, the molecules move farther apart. </span>
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Some plants make cones. Other plants make flowers. What is the purpose of flowers and cones
Semenov [28]

Answer:

Both cones and flowers produce seeds and are used for reproduction. ... The male cones release pollen which is carried by the wind to a female cone. A pollen tube is formed and pollen is transferred to fertilize the female cone's egg

5 0
3 years ago
1. Propane gas (C3H8) burns completely in the presence of oxygen gas (O2) to yield carbon dioxide gas (CO2) and water vapor (H2O
vovikov84 [41]
1) Balanced equation

C3H8 + 5O2 -> 3 CO2 + 4 H2O

2) 0.700 L C3H8

Given the pressure and temperature do not change, the molar ratio is equivalent to volume ratio

1molC3H8 / 5 mol O2 => 1 L C3H8 / 5 L O2

0.700 L C3H8 / x L O2 = 1 L C3H8 / 5 L O2 => x = 0.700 L C3H8 * 5 L O2 / 1 L C3H8

x = 3.500 L O2

3) CO2 produced

1 L C3H8 / 3 L CO2 = 0.700 L C3H8 / x L CO2 =>

x = 0.700 L C3H8 * 3 L CO2 / 1 L C3H8 = 2.100 L CO2

4) Water vapor produced

1) 1 L C3H8 / 4 L H2O = 0.700 LC3H8 / x L H2O =>

x = 0.700 L C3H8 * 4 L H20 / 1 L C3H8 = 2.800 L H2O
3 0
3 years ago
Most commercial sports drinks are
lions [1.4K]
C. sodium poor is the answer
7 0
2 years ago
Read 2 more answers
When an exothermic reaction occurs in a water solution, the temperature of the solution
iVinArrow [24]

Answer:

is hot

Explanation:

6 0
3 years ago
Read 2 more answers
From the enthalpies of reaction H2(g)+F2(g)→2HF(g)ΔH=−537kJ C(s)+2F2(g)→CF4(g)ΔH=−680kJ 2C(s)+2H2(g)→C2H4(g)ΔH=+52.3kJ calculate
DIA [1.3K]

Answer:

\Delta H for the given reaction is -2486.3 kJ

Explanation:

The given equation can be written as a combination of the following equation:

2H_{2}(g)+2F_{2}(g)\rightarrow 4HF(g)  ; \Delta H_{1}= (2\times -537kJ)=-1074 kJ

2C(s)+4F_{2}(g)\rightarrow 2CF_{4}(g)  ;  \Delta H_{2}=(2\times -680kJ)=-1360kJ

C_{2}H_{4}(g)\rightarrow 2C(s)+2H_{2}(g)  ;  \Delta H_{3}=-52.3kJ

-----------------------------------------------------------------------------------

C_{2}H_{4}(g)+6F_{2}(g)\rightarrow 2CF_{4}(g)+4HF(g)

\Delta H=\Delta H_{1}+\Delta H_{2}+\Delta H_{3}=(-1074-1360-52.3)kJ=-2486.3kJ

6 0
3 years ago
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