So you have x, then you square it to get x^2, then you minus 2x, then +3
The inverse is going backwards so you -3 then +2x then square root x
So you get square root x + 2x -3
I'm pretty sure this is right, sorry if I'm wrong.
Answer:
<em>m=-1/2</em>
Step-by-step explanation:
The equation is in y=mx+b form. M is the slope. In this equation, -1/2 is m.
Therefore the slope is -1/2.
<h3>
♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>
➷ Just divide the values:
213 / 4 = 53.25
He can make 53 cakes.
53 x 4 = 212
Subtract this from the original:
213 - 212 = 1
1 cup of flour is left over
<h3><u>
✽</u></h3>
➶ Hope This Helps You!
➶ Good Luck (:
➶ Have A Great Day ^-^
↬ ʜᴀɴɴᴀʜ ♡
Find the perimeter of the garden find out what kind of triangle the garden is for example if it is a right triangle it has to equal up to 90.
To find the area remember that A=b•h2 as a=area
Ok, so remember that the derivitive of the position function is the velocty function and the derivitive of the velocity function is the accceleration function
x(t) is the positon function
so just take the derivitive of 3t/π +cos(t) twice
first derivitive is 3/π-sin(t)
2nd derivitive is -cos(t)
a(t)=-cos(t)
on the interval [π/2,5π/2) where does -cos(t)=1? or where does cos(t)=-1?
at t=π
so now plug that in for t in the position function to find the position at time t=π
x(π)=3(π)/π+cos(π)
x(π)=3-1
x(π)=2
so the position is 2
ok, that graph is the first derivitive of f(x)
the function f(x) is increaseing when the slope is positive
it is concave up when the 2nd derivitive of f(x) is positive
we are given f'(x), the derivitive of f(x)
we want to find where it is increasing AND where it is concave down
it is increasing when the derivitive is positive, so just find where the graph is positive (that's about from -2 to 4)
it is concave down when the second derivitive (aka derivitive of the first derivitive aka slope of the first derivitive) is negative
where is the slope negative?
from about x=0 to x=2
and that's in our range of being increasing
so the interval is (0,2)
