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BlackZzzverrR [31]
3 years ago
7

HELP ASAP How many millimeters of mercury pressure does a gas exert at 3.16 atm?

Chemistry
2 answers:
Georgia [21]3 years ago
0 0

The conversion factor is 760 mmHg/atm.

3.1 atm * 760 mmHg/atm = 2356 m

azamat3 years ago
0 0
3.1=2356 is the millimeters amount
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Why was Rutherford's Gold Foil Experiment so important?
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Answer:

Answer is 'B' I think

Explanation:

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What is the mass in grams of 1.00 x 10 24 atoms of Mn?
Alex17521 [72]
<h3>Answer:</h3>

91.2 g Mn

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 1.00 × 10²⁴ atoms Mn

<u>Step 2: Identify Conversions</u>

Avogadro's Numer

[PT] Molar Mass of Mn - 54.94 g/mol

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                      \displaystyle 1.00 \cdot 10^{24} \ atoms \ Mn(\frac{1 \ mol \ Mn}{6.022 \cdot 10^{23} \ atoms \ Mn})(\frac{54.94 \ g \ Mn}{1 \ mol \ Mn})
  2. [DA] Multiply/Divide [Cancel out units]:                                                           \displaystyle 91.2321 \ g \ Mn

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

91.2321 g Mn ≈ 91.2 g Mn

7 0
3 years ago
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Yanka [14]

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What is the molarity of 2.00 L of a solution that contains 14.6 g NaCl?
White raven [17]

Answer: The molarity of the solution is 0.125 M

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

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where,

n = moles of solute

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moles of NaCl = \frac{\text {given mass}}{\text {Molar mass}}=\frac{14.6g}{58.5g/mol}=0.250mol

Now put all the given values in the formula of molality, we get

Molarity=\frac{0.250mol}{2.00L}=0.125M

Therefore, the molarity of the solution is 0.125 M

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