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Viktor [21]
3 years ago
6

Hydrogen and nitrogen react to form ammonia according to the reaction, 3 H2 + N2 â> 2 NH3. If 4.0 moles of H2 with 2.0 moles

of N2 are reacted, how many moles of NH3 would be produced?
a) 1 mol
b) 2 mol
c) 4 mol
d) 2.7 mol
Chemistry
1 answer:
Debora [2.8K]3 years ago
5 0

Answer:

d) 2.7 mol

Explanation:

  • 3 H2 + N2 → 2 NH3

limit reagent is H2:

∴ Mw H2 = 2.016 g/mol

∴ Mw N2 = 28.0134 g/mol

⇒ moles NH3 = (4.0 moles H2)×(2 mol NH3/3mol H2)

⇒ moles NH3 = 2.666 mol

⇒ moles NH3 ≅ 2.7 mol

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If 2 objects have the same density they must have the same
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Answer:

Explanation:

Density can be defined as mass divided by volume. But 2 objects made of the same material will have the same density regardless of their volume.

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3 years ago
Why do the pH scale generally range from 0 to 14 in aqueous solution?
zalisa [80]

Answer:

In aqueous solution the pH scale varies from 0 to 14, which indicates this concentration of hydrogen. Solutions with pH less than 7 are acidic (the value of the exponent of the concentration is higher, because there are more ions in the solution) and alkaline (basic) those with a pH higher than 7. If the solvent is pure water, the pH = 7 indicates neutrality of the solution

Explanation:

PH is a measure of how acidic or basic a liquid is. Specifically, from a dissolution. The acidity of a solution is essentially due to the concentration of hydrogen ions dissolved in it. In reality, the ions are not found alone, but are in the form of hydronium ions consisting of one oxygen molecule and three positively charged hydrogen. PH precisely measures this concentration. And to do it, we can use simple and very visual methods.

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3 years ago
When 50 ml of 1.000x10^-1m pb(no3)2 solution was added to 50 ml of 1.000x10^-1m nai solution?
podryga [215]

Balanced chemical reaction: Pb(NO₃)₂ (aq) + 2NaI(aq) → 2PbI₂(s) + 2NaNO₃(aq).

V(Pb(NO₃)₂) = 50 mL ÷ 1000 mL = 0.05 L, volume of solution.

c(Pb(NO₃)₂) = 0.1 mol/L; concentration of solution.

n(Pb(NO₃)₂) = c(Pb(NO₃)₂) · V(Pb(NO₃)₂).

n(Pb(NO₃)₂) = 0.1 mol/L · 0.05 L.

n(Pb(NO₃)₂) = 0.005 mol.

n(NaI) = c(NaI) · V(NaI).

n(NaI) = 0.1 mol/L · 0.05 L.

n(NaI) = 0.005 mol; amount of substance.

From chemical reaction: n(Pb(NO₃)₂) : n(NaI) = 1 : 2.

n(Pb(NO₃)₂) = 0.005 mol ÷ 2.

n(Pb(NO₃)₂) = 0.0025 mol; number of moles Pb(NO₃)₂ used.

n(NaI) = 0.005 mol; number of moles NaI used.

The limiting reagent is Pb(NO₃)₂.

n(PbI₂) = 0.005 mol.

m(PbI₂) = n(PbI₂) · M(PbI₂).

m(PbI₂) = 0.005 mol · 461 g/mol.

m(PbI₂) = 2.305 g; the theoretical yield of PbI₂.

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3 years ago
Determine the maximum number of electrons in the 2f designation
sergejj [24]
Google said

How many electrons fit in each shell around an atom?

The maximum number of electrons that can occupy a specific energy level can be found using the following formula:

Electron Capacity = 2n2

The variable n represents the Principal Quantum Number, the number of the energy level in question.

Energy Level
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1 K 2
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5 O 50
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Keep in mind that an energy level need not be completely filled before electrons begin to fill the next level. You should always use the Periodic Table of Elements to check an element's electron configuration table if you need to know exactly how many electrons are in each level.
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I need help in this :(
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Answer:

ok follow me twitter dm me for answer The Kid D is my twitter

Explanation:

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