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Alinara [238K]
3 years ago
13

Name 3 flammable liquids that you could use to start a campfire.

Chemistry
1 answer:
Svet_ta [14]3 years ago
4 0
Gasoline, kerosene, and lighter fluid.
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What mass of water is produced by the combustion 1.2 x 10 exp 26 molecules of butane
algol [13]

Answer:

<em>17.94 kg of water</em>

Explanation:

The combustion reaction of balanced butane (C₄H₁₀) is as follows:

2 C₄H₁₀ + 13 O₂ ⇒ 8 CO₂ + 10 H₂O

The amount of butane molecules can be transferred to moles to establish the stoichiometric relationship with water and calculate the moles of water that are formed:

6.02x10²³ molecules _____ 1 mol of butane

1.2x10²⁶ molecules _____ X = 199.34 moles of butane

<em>Calculation</em>: 1.2x10²⁶ molecules x 1 mol / 6.02x10²³ molecules = 199.34 moles of butane

According to the balanced equation:

2 moles butane _____ 10 moles of water

199.34 moles of butane _____ X = 996.68 moles of water

<em>Calculation</em>: 199.34 moles x 10 moles / 2 moles = 996.68 moles of water

And now, you can calculate the mass of the amount of moles obtained from water:

1 mole of water _____ 18 g

996.68 moles of water _____ X = <em>17.94 kg of water </em>

<em>Calculation</em>: 996.68 moles x 18g / 1 mole = 17940.20g ≡ 17.94 kg of water

Therefore, <em>the combustion of 1.2x10²⁶ butane molecules produces 17.94 kg of water</em>.

4 0
4 years ago
Gaseous butane, CH3(CH2)2CH, reacts with gaseous oxygen gas, O2, to produce gaseous carbon dioxide, CO2, and gaseous water, H2O.
weeeeeb [17]

Answer:

Percentage yield of carbon dioxide is 49.9%

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

2CH3(CH2)2CH3 + 13O2 —> 8CO2 + 10H2O

OR

2C4H10 + 13O2 —> 8CO2 + 10H2O

Next, we shall determine the masses of butane and oxygen that reacted and the mass of carbon dioxide produced from the balanced equation. This is illustrated below:

Molar mass of butane C4H10 = (12×4) + (10×1)

= 48 + 10

= 58 g/mol

Mass of C4H10 from the balanced equation = 2 × 58 = 116 g

Molar mass of O2 = 16 × 2 = 32 g/mol

Mass of O2 from the balanced equation = 13 × 32 = 416 g

Molar mass of CO2 = 12 + (16×2)

= 12 + 32

= 44 g/mol

Mass of CO2 from the balanced equation = 8 × 44 = 352 g

Summary:

From the balanced equation above,

116 g of butane reacted with 416 g of oxygen to produce 352 g of carbon dioxide.

Next, we shall determine the limiting reactant. This can be obtained as follow:

From the balanced equation above,

116 g of butane reacted with 416 g of oxygen.

Therefore, 34.29 g of butane will react with = (34.29 × 416) / 116 = 122.97 g of oxygen.

From the calculation made above, we can see clearly that only 122.97 g out of 165.7 g of oxygen reacted completely with 34.29 g of butane. Therefore, butane is the limiting reactant and oxygen is the excess reactant.

Next, we shall determine the theoretical yield of carbon dioxide.

In this case, we shall use the limiting reactant because it will give the maximum yield of carbon dioxide as all of it is used up in the reaction.

The limiting reactant is butane and the theoretical yield of carbon dioxide can be obtained as follow:

From the balanced equation above,

116 g of butane reacted to produce 352 g of carbon dioxide.

Therefore, 34.29 g of butane will react to produce = (34.29 × 352) / 116 = 104.05 g of carbon dioxide.

Therefore, the theoretical yield of carbon dioxide is 104.05 g

Finally, we shall determine the percentage yield of carbon dioxide as follow:

Actual yield of carbon dioxide = 51.9 g

Theoretical yield of carbon dioxide = 104.05 g

Percentage yield of carbon dioxide =?

Percentage yield = Actual yield /Theoretical yield × 100

Percentage yield of carbon dioxide = 51.9 / 104.05 × 100

Percentage yield of carbon dioxide = 49.9%

7 0
3 years ago
Chemicals are classified as health hazards when they pose which of the following hazardous effects?
AlexFokin [52]

Answer:

poisoning, breathing problems, skin rashes, allergic reactions, allergic sensitisation, cancer, and other health problems from exposure.

Explanation:

many hazardous chemicals are also classified as dangerous goods.

4 0
3 years ago
Which compound is an isomer of CH3CH2OH?
Aleksandr-060686 [28]
A)CH3OCH3 is the isomer of CH3CH2OH
8 0
3 years ago
Nuclear fission reactions can produce different radioisotopes. One of these radioisotopes
hichkok12 [17]
Based on the information provided,

The evidence that this nuclear reaction reaction represent transmutation is it formed different elements

hope this helps
7 0
3 years ago
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