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Snezhnost [94]
3 years ago
5

11 .As you are sitting in your chair the force of gravity is pulling you down. What force is causing you to stay in the chair in

stead of falling through the chair?
A.applied.

B.normal.

C.gravity.

D.friction.
Physics
2 answers:
Olin [163]3 years ago
5 0

Answer:B

Explanation:

As you are sitting on the chair, gravity tends to pull you downwards but the normal reaction exerted by the chair is just enough to keep you from falling downwards. It works in the upward direction

omeli [17]3 years ago
5 0

<u>Answer:</u>

Option(B).= Normal

<u>Explanation:</u>

Normal force is a type of contact force which is perpendicular to surface of contact of objects like the surface of chair that prevents us from falling downwards or that of table that prevents an object from falling from it.

By Newton's third law, every force has an equal and opposite reaction so when we sit on a chair the force of gravity pulls us down which is thus the force we apply on chair due to the pull and because of it, the chair applies an equal normal force on us which prevents us from falling down.

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Tom kicks a soccer ball on a flat, level field giving it an initial speed of 20 m/s at an angle of 35 degrees above the horizont
SVEN [57.7K]

Answer:

(a) 2.34 s

(b) 6.71 m

(c) 38.35 m

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Explanation:

u = 20 m/s, theta = 35 degree

(a) The formula for the time of flight is given by

T = \frac{2 u Sin\theta }{g}

T = \frac{2 \times 20 \times Sin35 }{9.8}

T = 2.34 second

(b) The formula for the maximum height is given by

H = \frac{u^{2} \times Sin^{2}\theta }{2g}

H = \frac{20^{2} \times Sin^{2}35 }{2 \times 9.8}

H  = 6.71 m

(c) The formula for the range is given by

R = \frac{u^{2} \times Sin 2\theta }{g}

R = \frac{20^{2} \times Sin 2 \times 35}{9.8}

R = 38.35 m

(d) It hits with the same speed at the initial speed.

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R = V/I

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