80.24% carbon, 9.62% hydrogen and 10.14% oxygen
1) Base: 100 g
C: 80.24 g
H: 9.62 g
O: 10.14 g
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100.00 g
2) Conversion to moles
C: 80.24 g / 12.00 g /mol = 6.687 mol
H: 9.62 g / 1.00 g/mol = 9.62 mol
O: 10.14 g / 16.00 g/mol = 0.63375 mol
3) Ratio
C:6.687 / 0.63375 = 10.55
H: 9.62 / 0.63375 = 15.18
O: 0.63375 / 0.63375 = 1
Given that the tenth of C is 0.5 you need to multiply all the numbers by 2 =>
C: 10.55 * 2 = 21.1--> 21
H: 15.18 * 2 = 30.36 -> 30
O: 1 * 2 = 2
=> C21 H30 O2
Answer: C21 H30 O2
Answer:
Half-reactions:
Cr³⁺ + 1e⁻ → Cr²⁺; Zn → Zn²⁺ + 2e⁻
Net ionic equation:
2Cr³⁺ + Zn → 2Cr²⁺ + Zn²⁺
Explanation:
The Cr³⁺ is reduced to Cr²⁺:
<h3>
Cr³⁺ + 1e⁻ → Cr²⁺ -Half-reaction 1-</h3>
Zn is oxidized to Zn²⁺:
<h3>
Zn → Zn²⁺ + 2e⁻ -Half-reaction 2-</h3>
Twice the reduction of Cr:
2Cr³⁺ + 2e⁻ → 2Cr²⁺
Now this reaction + Oxidation of Zn:
2Cr³⁺ + 2e⁻ + Zn → 2Cr²⁺ + Zn²⁺ + 2e⁻
<h3>2Cr³⁺ + Zn → 2Cr²⁺ + Zn²⁺ - Net ionic equation</h3>
In what terms thought ? Math or science or chemistry ???
The Oort cloud sometimes called the Öpik–Oort cloud it was first described in 1950 by Dutch astronomer Jan Oort
Answer: FeF3 Iron(III) fluoride
Explanation: 5.6 g = 1/10 mole Fe
11.3-5.6g F = 5.7 = 3/10 mole F
