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UNO [17]
4 years ago
9

How many mm are equal to 21 L. How many mg are equal to 9 g. How many grams are equal to 400 kg

Chemistry
1 answer:
liberstina [14]4 years ago
8 0
<span>How many mm are equal to 21 L? 

1 L = </span>1000000 mm

Convert:-

1000000 × 21 = <span>21000000

21 l = </span><span>21000000 mm

</span><span>How many mg are equal to 9 g?

1 g = 1000 mg

Convert:-

9 </span>× 1000 = 9000

9 g = 9000 mg
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Calcium chloride forms an ionic solid. how are the particles held together and arranged in the solid
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Calcium chloride forms an ionic compound with a regularly arranged lattice of oppositely charged ions.

The Na+ and Cl- ions are held together by strong electrostatic forces. 

Hope that helps


7 0
3 years ago
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Hydrogen is a possible future fuel. However, elemental hydrogen is rare, so it must be obtained from a hydrogen- containing comp
dimulka [17.4K]

Answer:

1.1 × 10² g

Explanation:

First, we will convert 1.0 L to cubic centimeters.

1.0 L × (10³ mL/1 L) × (1 cm³/ 1 mL) = 1.0 × 10³ cm³

The density of water is 1.0 g/cm³. The mass corresponding to 1.0 × 10³ cm³ is:

1.0 × 10³ cm³ × (1.0 g/cm³) = 1.0 × 10³ g

1 mole of water (H₂O) has a mass of 18 g, consisting of 2 g of H and 16 g of O. The mass of Hydrogen in 1.0 × 10³ g of water is:

1.0 × 10³ g H₂O × (2 g H/18 g H₂O) = 1.1 × 10² g

4 0
3 years ago
(First to answer gets some good) Order the following components of the universe from largest to smallest: Moon, planet,universe,
cluponka [151]

Answer:

Universe, galaxy, solar system, star, planet, moon and asteroid.

Explanation:

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4 years ago
Help ASAP! <br><br>a, b, c, or d??​
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Answer:

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3 years ago
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What is the acceleration of a 50kg object pushed with a force of 500 Newton’s
olasank [31]

Answer:

<h2>10 m/s²</h2>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

a =  \frac{f}{m} \\

f is the force

m is the mass

From the question we have

a =  \frac{500}{50}  =  \frac{50}{5}  = 10 \\

We have the final answer as

<h3>10 m/s²</h3>

Hope this helps you

5 0
3 years ago
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