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CH3 is the empirical formula for the compound.
A sample of a compound is determined to have 1.17g of Carbon and 0.287 g of hydrogen.
The number of atom or moles in the compound is
1.17 g C X 1 mol of C / 12.011 g C = 0.097411 mol of C.
0.287 g H x 1 mol of H / 1 g H = 0.28474 mol H.
This compound contains 0.097411 mol of carbon and 0.28474 mol of Hydrogen.
So we can represent the compound with the formula C0.974H0.284.
Subscripts in formulas can be made into whole numbers by multiplying the smaller subscript by the larger subscript.
we can divide 0.284 by 0.0974.
0.284 / 0.0974 = 3.
So here, Carbon is one and hydrogen is 3.
We can write the above formula as a CH3.
Hence the empirical formula for the sample compound is CH3.
For a detailed study of the empirical formula refer given link brainly.com/question/13058832.
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Answer:
The tendency of metals to lose electrons inorder to get stability is called electropositive nature ofmetals. In general most of the metalslose electrons from their valence shell due to weak force of attraction on the outermost shell.
"a quantity representing the amount of water vapor in the atmosphere or a gas."
Answer: 0.02 molecules
The mass of sodium chloride= 23+35.5 = 58.5g
No. Of moles= Molar mass of NaCI
1.17 divided by 58.5 = 0.02
