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Phoenix [80]
3 years ago
11

Write the balanced equation of aluminium + copper chloride and ammonium chloride + copper ​

Chemistry
1 answer:
Scorpion4ik [409]3 years ago
6 0

Answer:

2Al+3CuCl2=>3Cu + 2AlCl3

NH4Cl catalyses the oxidation of Cu

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If 6.4 miles of Fe react with excess O2, how many miles of Fe2O3 can be formed? 4 Fe + 3 O2 -> 2 Fe2O3
Yuri [45]
I'm assuming that by "miles" you mean moles.

If O2 is the excess reactant, that means Fe is the limiting reactant. That means that the amount of product being formed depends on the amount of Fe reactant present. To calculate the moles of Fe2O3 formed, start with the given 6.4 moles of Fe and use the mole to mole ratio given by the reaction as shown below:

6.4 mol Fe x \frac{2 mol Fe2O3}{4 mol Fe} = 3.2 mol Fe2O3
6 0
3 years ago
Suppose you were to quickly throw a ball in outer space. Would it slow down as quickly in space, as it does in Earth? Explain wh
Sholpan [36]

Answer:It would never stop until something hit the ball, to slow it down.

Explanation:

This is so because there is no gravitational pull in space.

7 0
3 years ago
How many moles are there in 3.612 x 1024 formula units of Na2SO4?
vitfil [10]

Answer:

<h3>Theanswer is 6 moles</h3>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L}  \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{3.612 \times  {10}^{24} }{6.02 \times  {10}^{23} }  \\

We have the final answer as

<h3>6 moles</h3>

Hope this helps you

5 0
3 years ago
A cube of an unknown metal measures 0.200 cm on one side. The mass of the cube is 52 mg. Which of the following is most likely t
Margarita [4]

Answer:

Option E. Zirconium

Explanation:

From the question given above, the following data were obtained:

Length of side (L) of cube = 0.2 cm

Mass (m) of cube = 52 mg

Name of the unknown metal =?

Next, we shall determine the volume of the cube. This can be obtained as follow:

Length of side (L) of cube = 0.2 cm

Volume (V) of the cube =?

V = L³

V = 0.2³

V = 0.008 cm³

Next, we shall convert 52 mg to g. This can be obtained as follow:

1000 mg = 1 g

Therefore,

52 mg = 52 mg × 1 g / 1000 mg

52 mg = 0.052 g

Thus, 52 mg is equivalent to 0.052 g.

Next, we shall determine the density of the unknown metal. This can be obtained as follow:

Mass = 0.052 g.

Volume = 0.008 cm³

Density =?

Density = mass / volume

Density = 0.052 / 0.008

Density of the unknown metal = 6.5 g/cm³

Comparing the density of the unknown metal i.e 6.5 g/cm³ with those given in table in the above, we can conclude that the unknown metal is zirconium

7 0
3 years ago
PLEASE HELP AND THANKS
Kamila [148]

Answer:

torque =force*distance

4 0
3 years ago
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