Answer:
Mechanism for top reaction is combustion while the side product at bottom path oximes
Explanation:
Hydroxiamine is a reducing agent that requires high temperature to combust in it'd ageous state to produced oxime while water is eliminated. The reverse is the case because the production of water during combustion I does not yield the fight result as it can e very irritating.
Increased temperature stimulates the protons to become free to combust and react with 2 butene and other aldehyde during chemical reaction.
PH + pOH = 14 ⇒ pOH = 14 - pH
pOH = 14 - 2.5
pOH = 11.5
[H⁺] = 10^(-pH) = 10^(-2.5)
[H⁺] = 0.003 M
[OH⁻] = 10^(-pOH) = 10^(-11.5) = 3 × 10⁻¹² M
[OH⁻] = 3 × 10⁻¹² M
pH = 2.5 implies one significant digit
They are both sources of power for objects that people use.
The value of the Gibbs free energy shows us that the reaction is spontaneous.
<h3>What is the Gibbs free energy?</h3>
The Gibbs free energy is a quantity that helps us to be able to determine the spontaneity of a reaction.
In order to obtain the Gibbs free energy, we must obtain the Ecell as follows; 0.799V - (-0.402V) = 1.201 V
Now;
△G = -nFEcell
△G = -(2 * 96500 * 1.201)
△G = -232kJ/mol
Learn more about free energy:brainly.com/question/15319033?
#SPJ1
Molar mass:
Ca(OH)₂ = 74.093 g/mol
Ca₃(PO₄)₂ = 310.17 g/mol
Mole ratio:
<span>2 Na</span>₃<span>PO</span>₄<span> + 3 Ca(OH)</span>₂<span> = Ca</span>₃<span>(PO</span>₄<span>)</span>₂<span> + 6 NaOH
</span>
3 x 74.093 g Ca(OH)₂ ----------- 310.17 g Ca₃(PO₄)₂
?? g Ca(OH)₂ ----------- 3.09 g Ca₃(PO₄)₂
Mass of Ca(OH)₂ = 3.09 x 3 x 74.093 / 310.17
Mas of Ca(OH)₂ = 686.84211 / 310.17
= 2.214 g of Ca(OH)₂
hope this helps!
