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Aleksandr-060686 [28]
2 years ago
8

Please answer grade 6th

Chemistry
2 answers:
BabaBlast [244]2 years ago
8 0

Answer:

<u>Earth's</u><u> </u><u>plates</u><u> </u><u>moving</u><u> </u><u>&</u><u> </u><u>colliding</u><u> </u><u>against</u><u> </u><u>one</u><u> </u><u>another</u><u>.</u>

Ludmilka [50]2 years ago
4 0

Answer:

The last one

Explanation:

I have done this before

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Change for a liquid state to a solid state is known as what phase change?
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B. To change from a liquid state to a solid state is called Freezing

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This number tells you the number of each type of atom in a compound.
KonstantinChe [14]

Answer:

avogadro's constant

Explanation:

this is the fixed number of the atoms in the molecule of an element

avogadro's law states that equal volumes of gases<em> </em><em>at</em><em> </em><em>the</em><em> </em><em>same</em><em> </em><em>temperature</em><em> </em><em>and</em><em> </em><em>pressure</em><em> </em><em> </em><em>contain</em><em> </em><em>equal</em><em> </em><em>numbers</em><em> </em><em>of</em><em> </em><em>molecules</em><em> </em>

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7 0
3 years ago
What is the nuclear equation for decay of Am - 241
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Americium is a radioactive element .

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Here alpha can be written as He too

3 0
1 year ago
if 5430 J of energy is used to heat 1.25 L of room temp. water (23.0 °C) whats the final temp of the water?
skelet666 [1.2K]

<span>We can use the heat equation,
Q = mcΔT </span>

 

<span>Where Q is the amount of energy transferred (J), m is the mass of the substance (kg), c is the specific heat (J g</span>⁻¹ °C⁻<span>¹) and ΔT is the temperature difference (°C).</span>


Density = mass / volume


The density of water = 0.997 g/mL

<span>Hence mass of 1.25 L (1250 mL) of water = 0.997 g/mL x 1250 mL</span>

<span>                                                                   = 1246.25 g</span>


Specific heat capacity of water = 4.186 J<span>/ g °C.</span>


Let's assume that there is no heat loss to the surrounding and the final temperature is T.

By applying the equation,

      5430 J = 1246.25 g x 4.186 J/ g °C x (T - 23) °C
(T - 23) °C = 5430 J / 1246.25 g x 4.186 J/ g °C
(T - 23) °C = 1.04 °C
               T = 1.04 °C + 23 °C
               T = 24.04 °C

Hence, the final temperature of the water is 24.04 °C.
4 0
3 years ago
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