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liraira [26]
3 years ago
7

An air conditioner works be stealing heat from the inside air and releasing the heat outside. It then pushes the cooled air back

inside with a fan. Once the cool air enters the house, it spreads by the process of _______. A. conduction B. condensation C. convection D. radiation
Chemistry
2 answers:
Ludmilka [50]3 years ago
7 0

Answer:

conduction

Explanation:

because I had it on Study Island from sr. Nadia

uysha [10]3 years ago
3 0

The answer is conduction

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What kind of chemical bonds are represented by the product in the following diagram?
katovenus [111]
The chemical bonds in CH4 are all single bonds. C only can bond 4 times because it needs 8 electrons in it's outer shell and only has four right now. The bonds represented are all single bonds because there are two electrons present on each side of the carbon. Two electrons, in this case, equals one bond.
4 0
3 years ago
The pH of a vinegar solution is 4.15. What is the H3O+ concentration of the solution?
riadik2000 [5.3K]
PH = -log [H3O+]
4.15 = -log [H3O+]
[H3O+] = 10^(-4.15)
[H3O+]= 7.08 × 10^-5
8 0
3 years ago
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When 136g of glycine are dissolved in of a certain mystery liquid , the freezing point of the solution is lower than the freezin
loris [4]

The given question is incomplete. The complete question is:

When 136 g of glycine are dissolved in 950 g of a certain mystery liquid X, the freezing point of the solution is 8.2C lower than the freezing point of pure X. On the other hand, when 136 g of sodium chloride are dissolved in the same mass of X, the freezing point of the solution is 20.0C lower than the freezing point of pure X. Calculate the van't Hoff factor for sodium chloride in X.

Answer: The vant hoff factor for sodium chloride in X is 1.9

Explanation:

Depression in freezing point is given by:

\Delta T_f=i\times K_f\times m

\Delta T_f=T_f^0-T_f=8.2^0C = Depression in freezing point

K_f = freezing point constant

i = vant hoff factor = 1 ( for non electrolyte)

m= molality =\frac{136g\times 1000}{950g\times 75.07g/mol}=1.9

8.2^0C=1\times K_f\times 1.9

K_f=4.32^0C/m

Now Depression in freezing point for sodium chloride is given by:

\Delta T_f=i\times K_f\times m

\Delta T_f=20.0^0C = Depression in freezing point

K_f = freezing point constant  

m= molality = \frac{136g\times 1000}{950g\times 58.5g/mol}=2.45

20.0^0C=i\times 4.32^0C\times 2.45

i=1.9

Thus vant hoff factor for sodium chloride in X is 1.9

3 0
2 years ago
When bismuth-212 undergoes alpha decay, it becomes which of the following?
Iteru [2.4K]

Answer: -

When bismuth-212 undergoes alpha decay, it becomes ²⁰⁸Tl

Explanation: -

Mass number of ²¹²Bi = 212

Atomic number of ²¹²Bi = 83

When alpha decay occurs the mass number decreases by 4 and the atomic number decreases by 2.

Mass number of daughter = 212 - 4 = 208

Atomic number of daughter = 83 - 2 = 81

It is the atomic number of Thallium Tl.

Thus the daughter nucleide is ²⁰⁸Tl.

8 0
2 years ago
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How does the volume of water change the solubility of sodium chloride in simple words?
kupik [55]

Answer:

When sodium chloride dissolves in water to make a saturated solution there is a 2.5 per cent reduction in volume. ... The solubility of salt does not change much with temperature, so there is little profit in using hot water.

3 0
3 years ago
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