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il63 [147K]
3 years ago
8

Find a polynomial function that has the given zeros. (There are many correct answers.) −4, 6

Mathematics
1 answer:
daser333 [38]3 years ago
5 0

If polynomial function vanishes at

x

=

a

, then

(

x

−

a

)

must be one of its factors.

Thus

(

x

−

7

)

,

(

x

−

4

−

√

6

)

and

(

x

−

4

+

√

6

)

are factors of the required polynomial.

The simplest polynomial that satisfies this is

(

x

−

7

)

(

x

−

4

−

√

6

)

(

x

−

4

+

√

6

)

=

(

x

−

7

)

{

(

x

−

4

)

−

√

6

}

{

(

x

−

4

)

+

√

6

}

=

(

x

−

7

)

{

(

x

−

4

)

2

−

6

}

=

(

x

−

7

)

(

x

2

−

8

x

+

16

−

6

)

=

(

x

−

7

)

(

x

2

−

8

x

+

10

)

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Step-by-step explanation:

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Through how many radians do the minute hand and the hour hand move between 1:00 p.m. and 1:45 p.m. (on the same day)? ​
timofeeve [1]

Answer:

π/8 radians

Step-by-step explanation:

THIS IS THE COMPLETE QUESTION

In 1 h the minute hand on a clock moves through a complete circle, and the hour hand moves through 1 12 of a circle. Through how many radians do the minute hand and the hour hand move between 1:00 p.m. and 1:45 p.m. (on the same day)?

SOLUTION

✓If the minute hand on a clock moves through complete circle in 1 hour, then it means that it goes through a circle and angle of circle in radians is 2π.

Between 1:00 p.m. and 1:45pm in the same day we have 45 minutes i.e (1.45 pm -1pm)

Within the 1hour minutes, the hand can move with complete cycle of 2π radians

Then At time t= 45minutes

Angle through the circle at 45 minutes= 45/60 ×2π radians

= 3π/2 radians

And if the hour hand goes through a complete cycle 1/12 as told in the question we have 1/2 × 2π radians

For t=45 minutes

Then 1/12 × 2π ×45/60

= π/8 radians

Hence, the minute hand and the hour hand move π/8 radians between 1:00 p.m. and 1:45 p.m.

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If you are dealt 4 cards from a shuffled deck of 52 cards, find the probability of getting two queens and two kings.
Bingel [31]

<u>Given</u>:

If you are dealt 4 cards from a shuffled deck of 52 cards.

We need to determine the probability of getting two queens and two kings.

<u>Probability of getting two queens and two kings:</u>

The number of ways of getting two queens is 4C_2

The number of ways of getting two kings is 4C_2

Total number of cases is 52C_4

The probability of getting two queens and two kings is given by

\text {probability}=\frac{\text {No.of fanourable cases}}{\text {Total no.of cases}}

Substituting the values, we get;

probability=\frac{4C_2 \cdot 4C_2}{52C_4}

Simplifying, we get;

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probability=\frac{36}{270725}

probability=0.000133

Thus, the probability of getting two queens and two kings is 0.000133

7 0
3 years ago
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