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Effectus [21]
3 years ago
10

Helppppppppppp please beg of you

Mathematics
1 answer:
Serjik [45]3 years ago
6 0

Answer:

9\frac{2}{6} or 9\frac{1}{3}

Step-by-step explanation:

3\frac{1}{2} x 2\frac{2}{3}

Make the mixed number a fraction.

\frac{7}{2} x \frac{8}{3}

Multiply straight across

\frac{56}{6} = 9\frac{2}{6}

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kogti [31]
8172/9=908 the answer is 908

4 0
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What is the slope of the line through the points (8, -2) and (8, -8)?
gulaghasi [49]

Answer:

Step-by-step explanation:

(-8+2)/(8-8)= -6/0= undefined

8 0
3 years ago
2/3 divided by 4/6 =
const2013 [10]
1 ? I checked on the calculator and it said 1
4 0
3 years ago
A matched-pairs t-test is NOT an appropriate way to analyze data consisting of which of the following? Measurements of annual in
o-na [289]

Answer:

Step-by-step explanation:

A matched pair t test is one in which the set of data is divided into two sets of data and the test is done to test the difference between the pairs. Sometimes this is called paired t test.\

This is done normally where one group of sample or population can be paired with other group of sample /population.

Hence

A .Measurements of annual income for each twin for 100 randomly selected pairs of twins -- True

B. Measurements of annual income for both individuals in pairs formed by matching 100 people from State A and 100 people from State B based on level of education -- True

C. Measurements of annual income for both individuals in pairs formed by assigning 100 people to pairs at random -- True

D. Measurements of annual income recorded for both spouses of 100 randomly selected married couples  --False here we cannot say paired as these people are not grouped under the same conditions.

7 0
4 years ago
A rope pulling a sled is sloped at 15° upward at the point of contact. The tension in the rope is 50.0 N. What is the horizontal
gizmo_the_mogwai [7]

Answer:

The horizontal component of the force is 48 N.

Step-by-step explanation:

The angle that the rope makes with with the horizontal is 15°, that means, the horizontal component of the force F_H is

cos(15^o)=\frac{F_H}{50N}

\boxed{ F_H=50N*cos(15^o)=48N}

4 0
4 years ago
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