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USPshnik [31]
3 years ago
10

Is 1/3 a repeating decimal ?

Mathematics
2 answers:
SpyIntel [72]3 years ago
7 0

Answer:

Yes.

Step-by-step explanation:

1/3 = 0.333333333

Vitek1552 [10]3 years ago
3 0

Answer:

yes i also poop on poop though so it is fun

Step-by-step explanation:

1/3= poop

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Helppppp❤️ Please please
kodGreya [7K]

Answer:

B and D

Step-by-step explanation:

I think this is the answer

7 0
3 years ago
5•1000000 is how many times as large as 5•10000
gizmo_the_mogwai [7]

Answer:

100 times

Step-by-step explanation:

<em>5•1000000</em> has 2 more zeros than <em>5•10000 </em>so that means the first number is 100 times larger than the second number! hope this helps and please mark as brainiest

3 0
3 years ago
Read 2 more answers
Mr. Rijo bought 49 bags of soil one week and 28 bags of soil the next week. Which expression correctly applies the
earnstyle [38]

Answer:

49 + 28 = 7(7 + 4)

Step-by-step explanation:

49 bags of soil one week

28 bags of soil the next week

49 + 28 bags of soil purchased in total

Find the GCF (Greatest Common Factor) of 49 and 28.

49/7 = 7

28/7 = 4 (GCF is 7 since it is the largest number that can divide both 49 and 28 equally)

Factor out the GCF + rewrite division above (optional for visualization)

49/7 = 7 -> 49 = 7 * 7

28/7 = 4 -> 28 = 7 * 4

49 + 28 = 7(7 + 4)

Let me know if you have any questions!

8 0
2 years ago
Help plz. What is the product of 2,419 x 5?
GalinKa [24]

Answer:

A

Step-by-step explanation:

U just gotta trust me plz give me brainliest tho

8 0
3 years ago
A Find the amount compounded annually on Rs 25,000 for 2 years if the rates of
STatiana [176]

Answer:

Amount = Rs. 30250 when Rate = 10%

<em>Amount = Rs. 31360 when Rate = 12%</em>

Step-by-step explanation:

Given

Principal, P = Rs.\ 25,000

Time, t = 2\ years

Rate; R_1 = 10\%

Rate; R_2 = 12\%

Number of times (n) = Annually

n = 1

Required

Determine the Amount for both Rates

Amount (A) is calculated by:

A = P(1 + \frac{r}{n})^{nt}

When Rate = 10%, we have:

Substitute 25,000 for P; 2 for t; 1 for n and 10% for r

A = 25000 * (1 + \frac{10\%}{1})^{1 * 2}

A = 25000 * (1 + \frac{10\%}{1})^{2}

A = 25000 * (1 + 10\%)^{2}

Convert 10% to decimal

A = 25000 * (1 + 0.10)^{2}

A = 25000 * (1.10)^{2}

A = 25000 * 1.21

A = 30250

Hence;

<em>Amount = Rs. 30250 when Rate = 10%</em>

When Rate = 12%, we have:

Substitute 25,000 for P; 2 for t; 1 for n and 10% for r

A = 25000 * (1 + \frac{12\%}{1})^{1 * 2}

A = 25000 * (1 + \frac{12\%}{1})^{2}

A = 25000 * (1 + 12\%)^{2}

Convert 12% to decimal

A = 25000 * (1 + 0.12)^{2}

A = 25000 * (1.12)^{2}

A = 25000 * 1.2544

A = 31360

Hence;

<em>Amount = Rs. 31360 when Rate = 12%</em>

7 0
3 years ago
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