I see the light moving exactly at speed equal to c.
In fact, the second postulate of special relativity states that:
"The speed of light in free space has the same value c<span> in all inertial frames of reference."
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The problem says that I am moving at speed 2/3 c, so my motion is a uniform motion (constant speed). This means I am in an inertial frame of reference, so the speed of light in this frame must be equal to c.
<h2>
The magnitude of the average force acting on the ball during the collision is 340.57 N</h2>
Explanation:
Force is given by rate of change of momentum.
Mass of bullet = 555 g = 0.555 kg
Initial velocity = 14.9 m/s
Final velocity = -12.1 m/s - Opposite direction
Change in momentum = 0.555 x 14.9 - 0.555 x (-12.1)
Change in momentum = 14.985 kg m/s
Time taken = 0.044 s
Rate of change of momentum = Change in momentum ÷ Time
Rate of change of momentum = 14.985 ÷ 0.044
Rate of change of momentum = 340.57 N
Force = 340.57 N
The magnitude of the average force acting on the ball during the collision is 340.57 N
Answer:
С. 30 m
Explanation:
Given the following data;
Initial velocity, U = 12m/s
Final velocity, V = 18m/s
Acceleration, a = 3m/s²
To find the distance, we would use the third equation of motion;
V ² = U² + 2aS
Substituting into the equation, we have
18² = 12² + 2*3*S
324 = 144 + 6S
6S = 324 - 144
6S = 180
S = 180/6
Distance, S = 30 meters.
Answer:
Umm...I guess mainly the percentage of successful ejaculations into the womb would be decreased. It also would suggest a malfunction in the testicles. The fertilizing process would also be less succesfull.
Explanation:
Not sure if this was a serious question or not.....
