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Alexxandr [17]
2 years ago
7

If my indicater shows a oh of 12 would it be acidic ,alkalinic or nuetral​

Physics
1 answer:
AleksandrR [38]2 years ago
7 0

Explanation:

I m in debt in a country of a person trained and experienced and professional career of ur face except that's a nice weekend her to play with hf I m in English language learners are very much I love it and I m in a Haystack of a sqaure is a song called and said know if u r my name on my dic is used for u class of her send you an email doesn't matter if you do u know if I m in English dictionary is used to post again and I am from completed my homework Yara tune bhagat singh said on ur Wall Street no no I don't have any questions please contact us ☺️ and

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2 years ago
You push on a 30 kg box with a force of 120 N. What is the acceleration of the box2​
kumpel [21]

Answer:

6

Explanation:

120/30=6

8 0
2 years ago
Crystal can ride her bike 10 miles in 2.1 hours. What is her velocity
masha68 [24]

Answer:

v = 4.76 m/s

Explanation:

Given,

The distance traveled by her bike, d = 10 miles

The time of her travel, t = 2.1 m/s

The velocity of an object is defined as the distance traveled by the object to the time of travel. Therefore,

                          V = d/t   m/s

                              = 10 / 2.1

                              = 4.76 m/s

Hence, The velocity of her bike is, V = 4.76 m/s

6 0
3 years ago
A man's higher initial acceleration means that a man can outrun a horse over a very short race. A simple - but plausible - model
Lera25 [3.4K]

Answer:

 t_man = 10.16 s,   t_horse = 10.73 s,  the winner is the man

Explanation:

To solve this problem we are going to find the time of each one separately.

Man we look for distance and time during acceleration

         x₁ =  v₀ t₁ + ½ a₁ t₁²

as it comes out of rest its initial velocity is zero

        x₁ = ½ a₁ t₁²

        x₁ = ½ 6.0 1.8²

        x₁ = 9.72 m

at this point its speed is

        v₁ = v₀ + a t

        v₁ = 0 + 6  1.8

        v₁ = 10.8 m / s

From here on it continues at constant speed, the distance that the man needs to travel from the point where the man leaves at 100m is

        x₂ = 100 - x₁

        x₂ = 100- 9.72

        x₂ = 90.28 m

the time for this part is

        v₁ = x₂ / t₂

         t₂ = x₂ / v₂

         t₂ = 90.28 / 10.8

         t₂ = 8.36 s

the total time for the man is

        t_man = t₁ + t₂

        t _man = 1.8 + 8.36

        t_man = 10.16 s

We repeat the calculation for the horse

distance traveled during the acceleration period

         x₃ = v₀ t + ½ a₂ t₃²

as part of rest its initial velocity is zero

        x₃ = ½  a₂ t₃²

        x₃ = ½  5.0  4.8²

        x₃ = 57.6 m

the velocity at this point is

         v₃ = v₀ + a₂ t₃

         v₃ = 0 + 5  4.8

         v₃ = 24 m / s

the rest of the route is at constant speed, the remaining distance

         x₄ = 200 - x₃

         x₄ = 200 - 57.6

         x₄ = 142.4 m

the time to go through it is

         t₄ = x₄ / v₃

         t₄ = 142.4 / 24

         t₄ = 5.93 s

the total time for the horse is

         t_horse = t₃ + t₄

         t_horse = 4.8 + 5.93

         t_horse = 10.73 s

when we compare the times we see that the man arrives a little before the horse, the winner is the man

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