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4 years ago

Which statements about acceleration are true?

Physics

2 answers:

ANTONII [103]4 years ago

6 0

b. for acceleration , you must have a number , a unit, and a direction

c. to calculate acceleration , divide the change in velocity by the change in time .

a. the symbol for acceleration

larisa86 [58]4 years ago

5 0

C is the correct answer, hope it helps

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A round pipe of varying diameter carries petroleum from a wellhead to a refinery. At the wellhead, the pipe's diameter is 50.9 c

seraphim [82]

Answer:

Flow rate 2.34 m3/s

Diameter 0.754 m

Explanation:

Assuming steady flow, the volume flow rate along the pipe will always be constant, and equals to the product of flow speed and cross-section area.

The area at the well head is

$A = \pi r_w^2 = \pi (0.509/2)^2 = 0.203 m^2$

So the volume flow rate along the pipe is

$\dot{V} = Av = 0.203 * 11.5 = 2.34 m^3/s$

We can use the similar logic to find the cross-section area at the refinery

$A_r = \dot{V}/v_r = 2.34 / 5.25 = 0.446 m^2$

The radius of the pipe at the refinery is:

$A_r = \pi r^2$

$r^2 =A_r/\pi = 0.446/\pi = 0.141$

$r = \sqrt{0.141} = 0.377m$

So the diameter is twice the radius = 0.38*2 = 0.754m

6 0

3 years ago

Free points im poor so only 9

mash [69]

Answer:

i feel bad

Explanation:

7 0

4 years ago

Read 2 more answers

The sudden drain of a magma chamber can form a caldera.<br><br> True<br><br> False

Sladkaya [172]

Maybe true not sure......?

6 0

3 years ago

Read 2 more answers

Which law best describes this behavior of gases in the Sun?

Anvisha [2.4K]

Answer:

The extreme pressure from the weight of the gases that make up the Sun raises the temperature of the core enough for the nuclear reactions to take place, Which law best describes this behavior of gases in the Sun? A. Charles law.

Explanation:

if it is helpful....... plzz like and follow

7 0

3 years ago

A proton enters a magnetic field (B = 5.00 x 10^-2 T INTO THE PAGE) with

poizon [28]

Answer:

r = 1.16 m

Explanation:

It is given that,

Magnetic field, $B=5.6\times 10^6\ m/s$

Velocity of proton, $v=5.6\times 10^6\ m/s$

We need to find the radius (in m) of the circular path the particle will follow when it is travelling within the magnetic field. The radius followed by the proton is given by :

$r=\dfrac{mv}{qB}$

m is mass of proton, $m=1.67\times 10^{-27}\ kg$

So,

$r=\dfrac{1.67\times 10^{-27}\times 5.6\times 10^6}{1.6\times 10^{-19}\times 5\times 10^{-2}}\\\\r=1.16\ m$

So, the radius of circular path is 1.16 m.

5 0

3 years ago