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jasenka [17]
3 years ago
12

How do you solve this? I am so confused. This is Chemistry 1 HON and its dimensional analysis. It would help me so much if someo

ne explained it and showed work please and thank you...

Chemistry
1 answer:
Mekhanik [1.2K]3 years ago
4 0

1. 150 yards

2. 4320

3. 144

4. 2688

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Oksi-84 [34.3K]

Answer:

2K + Br2 --> 2KBr is the answer

4 0
3 years ago
The smallest unit of an element that retains all the characteristics of that element is called a(n)
Maksim231197 [3]
<span>The smallest unit of an element that retains all the characteristics of that element is called an A. atom.
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3 years ago
There are four branched isomers of hexane. draw bond-line structures of all four of its isomers.
Finger [1]
C-c-c-c-c
   |
   c

c-c-c-c-c
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c-c-c-c
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3 0
3 years ago
If a gas occupies 1532.7 mL at standard temperature, what volume does it occupy at 49.4 ºC if the pressure remains constant?
ElenaW [278]

Answer:

a. 1810mL

Explanation:

When conditions for a gas change under constant pressure (and the number of molecules doesn't change), it follows Charles' Law:

\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}  where the temperatures must be measured in Kelvin

To convert from Celsius to Kelvin, add 273, or use the equation:  T_C+273=T_K

For this problem, one must also recall that standard temperature is 0°C (or 273K).

So, T_1 = 273[K], and T_2 = (49.4+273)[K]=322.4[K].

\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}

\dfrac{(1532.7[mL])}{(273[K])}=\dfrac{V_2}{(322.4[K])}

\dfrac{(1532.7[mL])}{(273[K\!\!\!\!\!{-}])}(322.4[K\!\!\!\!\!{-}] )=\dfrac{V_2}{(322.4[K]\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{----})}(322.4[K]\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{----})

1810.04571428[mL]=V_2

Adjusting for significant figures, this gives V_2=1810[mL]

4 0
2 years ago
Pls Help!!!!! ASAP!!!!​
HACTEHA [7]

Answer:

do u need help mentally?

Explanation:

:>

7 0
2 years ago
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