First calculate the Ar of the compound.. ( Ar of C6H12O6 is 180)
Then divide the At of the required element by 180 and multiply by 100...
so, for carbon 12 * 6 = 72 (THERE ARE 6 CARBON ATOM)
(72/180) * 100 =40%
ITS THE SAME FOR THE OTHER 2 ELEMENT
Explanation:
color (intensive)
density (intensive)
volume (extensive)
mass (extensive)
boiling point (intensive): the temperature at which a substance boils
melting point (intensive): the temperature at which a substance
Answer:- 27.7 grams of
are produced.
Solution:- The balanced equation is:

let's convert the grams of each reactant to moles and calculate the grams of the product and see which one gives least amount of the product. This least amount would be the answer as the least amount we get is from the limiting reactant.
Molar mass of
= 207.2+2(126.90) = 461 gram per mol
let's do the calculations for the grams of the product for the given grams of each of the reactant:

= 

= 
From above calculations, NaI gives least amount of
, so the answer is, 27.7 g of
are produced.
Answer:
48 volts
Explanation:
Voltage (E) = Current (I) x Resistance (R), or E = IR.