Answer:
The rate of the reaction will increase by a factor of 9.
Explanation:
Hello,
In this case, considering the given second-order reaction, whose rate law results:
![r=k[A] [B]^2](https://tex.z-dn.net/?f=r%3Dk%5BA%5D%20%5BB%5D%5E2)
We easily infer that at constant concentration of A but tripling the concentration of B, we are going to obtain the following increasing factor while holding the remaining variables constant:
![Increase\ factor=\frac{r_{final}}{r_{initial}} =\frac{k[A][3*B]^2}{k[A][B]^2} =\frac{3^2}{1} \\Increase\ factor=9](https://tex.z-dn.net/?f=Increase%5C%20factor%3D%5Cfrac%7Br_%7Bfinal%7D%7D%7Br_%7Binitial%7D%7D%20%3D%5Cfrac%7Bk%5BA%5D%5B3%2AB%5D%5E2%7D%7Bk%5BA%5D%5BB%5D%5E2%7D%20%3D%5Cfrac%7B3%5E2%7D%7B1%7D%20%5C%5CIncrease%5C%20factor%3D9)
Best regards.
Answer:
Because energy is conserved, the kinetic energy of a block at the bottom of a frictionless
ramp is equal to the gravitational potential energy of the block at the top of the ramp. This
value is proportional to the square of the block’s velocity at the bottom of the ramp.
Therefore, the block’s final velocity depends on the height of the ramp but not the steepness
of the ramp
Explanation:
Answer:
I don't <u>understand</u><u> </u><u>your</u><u> </u><u>question</u><u> </u>
Unit of M is also mole/L, where mole is the moles of solute and L is the volume of the solution. The latter is given: 158 mL or 0.158 L. So we need to find out the moles of NH4Br.
Moles of NH4Br = Mass of NH4Br/molar mass of NH4Br = 17.0g/(14+1*4+79.9)g/mol = 0.1736 mole.
So, the molarity of the solution = 0.1736mole/0.158L = 1.10 mole/L = 1.10 M
Atomic mass Ar => 39.948 a.m.u
39.948 g --------------- 6.02x10²³ atoms
?? g -------------------- 3.8x10²⁴ atoms
(3.8x10²⁴) x 39.948 / 6.02x10²³ => 250 g
hope this helps!
