The equivalent expression to 11^-7 × 11^5 is one over eleven raised to the second power. option A
Exponential
11^-7 × 11^5
= 11^(-7+5)
= 11^(-2)
= 1 / 11²
Options:
one over eleven raised to the second power
(1/11)²
one over eleven raised to the power of negative two
(1/11)^-2
11^2
−11^2
Therefore, the equivalent expression to 11^-7 × 11^5 is one over eleven raised to the second power.
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Answer:
P
Step-by-step explanation:
A translation 5 units to the right , followed by a 180-degree counterclockwise rotation about the origin
Answer:
SA = 7.08 in²
Step-by-step explanation:
We can use the following method to solve the given problem
SA = 2B + LA
Where LA
LA = 4.72* 0.05* 15= 3.54
And
C = 2πr
Where
C = 4.72in
π = 3.14
Substituting, we have
4.72 = 2*3.14*r
Making r the subject of formula
r = 0.75in
Solve for the area of CD
A = πr²
Substituting the values we have
A = 3.14 *(0.75)²
A= 1.77 in²
Solving for surface area of the stack
SA = 2(1.77) + 3.54
SA = 7.08 in²
Answer:
(4,9) is in quarter I and (4,-9) is in quarter IV of the graph. (4,-9) is the point (4,9) reflected over the x-axis. they are similar bc both have 4 as their x coordinate.
Step-by-step explanation:
