3 years ago

The simplest form of formula is a:

Physics

1 answer:

andrezito [222]3 years ago

4 0

C) Empirical formula .................. Hope it helps, Have a nice day :)

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A ladybug has a mass of 0.01 g and a velocity of 0.6 m/s. What is his momentum?

Alex

0.000006‬kgm/s

Explanation:

Given parameters:

Mass = 0.01g

Velocity = 0.6m/s

Unknown:

Momentum = ?

Solution:

The momentum of a body is the product of its mass and velocity. It is subject to the impact a body in motion will have .

Momentum = mass x velocity

The unit is in kgm/s

We need to convert the mass to kilograms:

1000g = 1kg

0.01g = x kg ; 0.00001‬kg

Input the parameter:

Momentum = 0.00001 x 0.6 = 0.000006‬kgm/s

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Answer:

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A standing wave of the third overtone is induced in a stopped pipe, 3 m long. The speed of sound is 340 m/s. The number of antin

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Answer:

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The water from a fire hose follows a path described by y equals 3.0 plus 0.8 x minus 0.40 x squared (units are in meters). If

ivanzaharov [21]

Explanation:

It is given that, the water from a fire hose follows a path described by equation :

$y=3+0.8x-0.4x^2$ ........(1)

The x component of constant velocity, $v_x=5\ m/s$

We need to find the resultant velocity at the point (2,3).

Let $\dfrac{dx}{dt}=v_x$ and $\dfrac{dy}{dt}=v_y$

Differentiating equation (1) wrt t as,

$\dfrac{dy}{dt}=0.8\times \dfrac{dx}{dt}-0.8x\times \dfrac{dx}{dt}$

$v_y=0.8\times v_x-0.8x\times v_x$

$v_y=0.8v_x(1-x)$

When x = 2 and $v_x=5\ m/s$

So,

$v_y=0.8\times 5\times (1-2)$

$v_y=-4\ m/s$

Resultant velocity, $v=\sqrt{v_x^2+v_y^2}$

$v=\sqrt{5^2+(-4)^2}$

v = 6.4 m/s

So, the resultant velocity at point (2,3) is 6.4 m/s. Hence, this is the required solution.

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