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antiseptic1488 [7]
3 years ago
8

An unpolarized light beam with intensity I0 is first passed through an ideal polarizer. At this instant, the light is polarized.

We then pass that light through 3 more identical polarizers having parallel axes of transmission to each other. If the transmission axis of the final polarizer makes an angle of 45 ∘∘ with the electric field direction of the polarized light, what is the intensity of the emerging light?
Physics
1 answer:
-BARSIC- [3]3 years ago
7 0

Answer:

The intensity of the emerging light reduced to 25%

Explanation:

Given :

Unpolarized light intensity = I_{o}

Initial polarizer angle = 0°

Final polarizer angle between optic axis and transmission axis = 45°

Unpolarized light passes through first polarizer the intensity reduces to half.

after second polarizer the intensity is half till the last polarizer,

   I_{3} = \frac{I_{o} }{2} \cos^{2} 45

   I_{3} = \frac{I_{o} }{4}

Therefore, the intensity of the emerging light reduced to 25%

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Enrique is given information about a satellite orbiting Earth. R = 3. 8 Ă— 108 m T = 18 days In order to calculate the tangentia
NISA [10]

The first step that  Enrique must take in order to calculate the tangential speed of the satellite is to convert the period from days to seconds.

We know that the SI unit of speed is meter per second and now, we with to obtain the tangential speed of the satellite.

Since the period is given in days, the first step is to convert the period from days to seconds.

Learn more: brainly.com/question/17638582

6 0
2 years ago
When a mass of 0.350 kg is attached to a vertical spring and lowered slowly, the spring stretches 12.0 cm. The mass is now displ
Ray Of Light [21]

Answer:

period of oscillations is 0.695 second

Explanation:

given data

mass m = 0.350 kg

spring stretches x = 12 cm = 0.12 m

to find out

period of oscillations

solution

we know here that force

force = k × x   .........1

so force = mg =  0.35 (9.8)  = 3.43 N

3.43 = k × 0.12

k = 28.58 N/m

so period of oscillations is

period of oscillations = 2π × \sqrt{\frac{m}{k} }   ................2

put here value

period of oscillations = 2π × \sqrt{\frac{0.35}{28.58} }  

period of oscillations = 0.6953

so period of oscillations is 0.695 second

4 0
3 years ago
Two charged objects separated by some distance attract each other. If the charges on both objects are doubled with no change in
Serggg [28]

Answer:

(a) The force between them quadruples

Explanation:

According to coulomb's law, initial force between the two charged objects is given as;

F_1=\frac{Kq_1q_2}{r^2}

where;

k is coulomb's constant

q₁ is the charge on the first object

q₂ is the charge on the second object

r is the distance between the two objects

When the charges on both objects are doubled, then;

q₁ = 2q₁

q₂ = 2q₂

Force between the two charged objects will become

F_2 = \frac{K2q_12q_2}{r^2} =  \frac{4Kq_1q_2}{r^2} = 4(\frac{Kq_1q_2}{r^2}) = 4F_1

Therefore, the force between them quadruples

4 0
3 years ago
I need help with this physics question
insens350 [35]
It's impossible to describe WHERE a place is without mentioning ANOTHER place.

... Across the street from -- the bank.
... Next door to -- my house.
... 30 miles west of -- Chicago.
... Up above -- the tree.
... Two days ride out of -- Tulsa.
... Halfway home from -- school.
... Twice as far from Earth as -- the moon is.
... The first seat in -- the second row.
... Behind -- the dog's left ear.
... At the bottom of -- the pool.
... On the tip of -- my tongue.
... In the front seat of -- the car.
... I saw you in -- my dream.
... You're always on -- my mind.

The question is trying to get you to realize that to get from a reference point to a certain position, you have to know

How far
and
In what direction.
4 0
3 years ago
Two vectors A and B are at right angles to each other. The magnitude of A is 3.00. What should be the length of B, so that the m
AfilCa [17]

Answer: length of B =4.00

Explanation:

for  the vectors A and B and the angle between them as  x.

Magnitude of the sum of A and B is  given as = √(A²+B²+2ABcosx

where

Magnitude of A  = 3.00

Magnitude of the sum of A and B is  5.00

5.00=√(A²+B²+2ABcos90°

5.00= √3² +b² +0

5²= 3² +b²

25=9+b²

b²= 25-9

b² = 16

b=  √16

b= 4

7 0
3 years ago
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