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miss Akunina [59]
3 years ago
13

A tourist drops a penny off the Empire State Building. The penny hits the ground 12 seconds later. What is the velocity of the p

enny when it hits the ground?
Physics
1 answer:
trasher [3.6K]3 years ago
5 0

Answer:

117.6 m/s downward

Explanation:

The penny is moving with uniform accelerated motion (free fall motion), so we can find its vertical velocity at time t with the following suvat equation:

v = u + at

where

v is the velocity at time t

u is the initial velocity

a is the acceleration

The penny starts at rest, so

u = 0

Also, the acceleration is the acceleration of gravity,

a=g=-9.8 m/s^2

where we have chosen upward as positive direction, so the acceleration is negative, since it is downward.

Substituting t = 12 s, we find the velocity of the penny when it hits the ground:

v=0 + (-9.8)(12)=-117.6 m/s

downward, since the sign is negative.

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Answer:

Explanation:

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As gravity force is proportional to the inverse of the square of the distance,

doubling the distance will reduce the weight to a forth.

F' = GmM/(2d)²

F' = ¼GmM/d²

F' = ¼F = ¼(4000)

F' = 1000 N

6 0
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6 0
3 years ago
Which of the following best describes each particle?
Nana76 [90]

Answer:

C. Protons are positive, neutrons are neutral, and electrons are negative

4 0
3 years ago
If u shine a light of frequency 375Hz on a double slit setup, and u measure the slit separation to be 950nm and the screen dista
xxMikexx [17]

Answer:

Y = 3.39 x 10⁶ m

Explanation:

We will use Young's Double Slit formula here:

Y = \frac{\lambda L}{d}

where,

Y = Fringe spacing = ?

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L = screend distance = 4030 nm = 4.03 x 10⁻⁶ m

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Therefore,

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kow [346]

Answer:

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