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Keith_Richards [23]
3 years ago
5

2. ATO kg bouting ball would require what force to accelerate down an alleyway at a rate of ons?

Chemistry
1 answer:
Mars2501 [29]3 years ago
6 0

Answer:

  • 2. 30N
  • 3. 5,000N
  • 4. 15 kg
  • 5. 2,800 kg

Explanation:

<em>2. A 10 kg bowling  ball would require what force to accelerate down an alleyway at a rate of 3m/s² ?</em>

Notice that I completed the question with the garbled and missing values:

<u>Data:</u>

  • F = ?
  • m = 10 kg
  • a = 3m/s²

<u />

<u>Physical principles:</u>

  • Newton's second law: F=m\times a

<u>Solution:</u>

  • Substitute and compute

        F=10kg\times 3m/s^2=30N

<em></em>

<em>3. Salty has a car that accelerates at 5 m/s². If the car has a mass of 1000 kg, how much force does the car produce?</em>

Notice that I arranged the typos.

<u />

<u>Data:</u>

  • F = ?
  • m = ?
  • a = ?

<u>Physical principles:</u>

  • Newton's second law: F=m\times a

<u>Solution:</u>

  • Substitute and compute

       F=1,000kg\times5m/s^2=5,000N

<em>4. What is the mass of a falling rock if it produces a force of 147 N?</em>

<u>Data:</u>

  • F = 147N
  • m = ?
  • a = falling rock

<u>Physical principles:</u>

  • neglecting air resistance ⇒ a = g: gravitational acceleration: 9.8m/s²
  • Newton's second law: F=m\times a

<u>Solution:</u>

  • Clear m from Newton's second law

         m=\dfrac{F}{a}

  • Substitute with F = 147 N and a = g = 9.8m/s², and compute

      m=\dfrac{147N}{9.8m/s^2}=15Kg

<em></em>

<em>5. What is the mass of a truck if it produces a force of 14,000 N while accelerating at a rate of 5 m/s²?</em>

<u>Data:</u>

  • F= 14,000N
  • m = ?
  • a =​ 5m/s²

<u>Physical principles:</u>

  • Second Newton's law: F=m\times a

<u>Solution:</u>

  • Clear m from Newton's second law

         m=\dfrac{F}{a}

  • Substitute with F = 14,000 N and a = 5m/s², and compute

      m=\dfrac{14,000N}{5m/s^2}=2,800kg

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alexgriva [62]
I think the answer would be dependent variable. An unknown or changeable quantity is called a dependent variable. It <span>is what you measure in the experiment and what is affected during the experiment. Hope this answers the question. Have a nice day.</span>
6 0
3 years ago
20. What volume of 0.350M KMnO4 solution must be diluted to prepare 600. mL of
Dafna1 [17]

Answer:

25.7 mL

Explanation:

Step 1: Given data

  • Initial volume (V₁): ?
  • Initial concentration (C₁): 0.350 M
  • Final volume (V₂): 600 mL
  • Final concentration (C₂): 0.150 M

Step 2: Calculate the volume of the initial solution

We have a concentrated solution and we want to prepare a diluted one. We can calculate the initial volume using the dilution rule.

C₁ × V₁ = C₂ × V₂

V₁ = C₂ × V₂ / C₁

V₁ = 0.150 M × 600 mL / 0.350 M

V₁ = 25.7 mL

3 0
3 years ago
Match the following with their correct molecular weight. 2-butanone Propyl acetate 4-methyl-2-pentanone Butyl acetate Methanol E
Hatshy [7]

Answer:

2-butanone = 72.11 g/mol (option F)

Propyl acetate  = 102.13 g/mol (option C)

4-methyl-2-pentanone = 100.16 g/mol (option D)

Butyl acetate = 116.16 g/mol (option B)

Methanol = 32.04 g/mol (option E)

Ethanol  = 46.07 g/mol (option A)

Explanation:

Step 1: Data given

Molar mass of C = 12.01 g/mol

Molar mass of H = 1.01 g/mol

Molar mass of O = 16.00 g/mol

Step 2:

2-butanone = C4H8O

⇒ 4*12.01 + 8*1.01 + 16.00 = 72.11 g/mol (option F)

Propyl acetate = C5H10O2

⇒ 5*12.01 + 10*1.01 + 2*16.00 = 102.13 g/mol (option C)

4-methyl-2-pentanone = C6H12O

⇒ 6*12.01 + 12*1.01 + 16.00 = 100.16 g/mol (option D)

Butyl acetate = C6H12O2

⇒ 6*12.01 + 12*1.01 + 2*16.00 = 116.16 g/mol (option B)

Methanol = CH3OH = CH4O

⇒ 12.01 + 4*1.01 + 16.00 = 32.04 g/mol (option E)

Ethanol = C2H5OH = C2H6O

⇒ 2*12.01 + 6*1.01 + 16.00 = 46.07 g/mol (option A)

4 0
3 years ago
What is the molar mass of cholesterol if 0.00105 mol weigh 0.406 g?
Rudiy27

Answer:

387 g/mol

Explanation:

The molar mass is a ratio comparing a substance's mass and molar value. The specific ratio looks like this:

Molar Mass (g/mol) = mass (g) / moles

You can plug the given values into the ratio to find the molar mass.

Molar Mass = mass / moles

Molar Mass = 0.406 g / 0.00105 mol

Molar Mass = 387 g/mol

8 0
2 years ago
What is the total number of electron pairs shared between the carbon atom and one of the oxygen atoms in a carbon dioxide molecu
TEA [102]
The answer is 2 pairs. The carbon atom has 4 electrons and oxygen atom has 6 electrons. The purpose of shared electron is to get 8 electrons at the outer layer. So the carbon atom needs to share 4 electrons which is 2 pairs with oxygen to be stable.
7 0
3 years ago
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