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mafiozo [28]
3 years ago
11

his is the chemical formula for epinephrine (the main ingredient in adrenaline): C9H13O3N A biochemist has determined by measure

ments that there are 33. moles of carbon in a sample of epinephrine. How many moles of nitrogen are in the sample?
Chemistry
1 answer:
Len [333]3 years ago
5 0

Answer:

3.67 moles of N

Explanation:

The epinephrine's chemical formula is: C₉H₁₃O₃N

We were told that a chemist found that in a mesaure of epinephrine, he found 33 moles of C

We must know that 9 moles of C are in 1 mol of C₉H₁₃O₃N so, let's make a rule of three:

If 9 moles of C are found in 1 mol of C₉H₁₃O₃N

Therefore 33 moles of C must be found in (33 .1) / 9 = 3.67 moles of C₉H₁₃O₃N

There is a second rule of three, then.

In 1 mol of C₉H₁₃O₃N we have 1 mol of N

Then, 3.67 moles C₉H₁₃O₃N must have (3.67 . 1) / 1 = 3.67 moles of N

Remember 1 mol of C₉H₁₃O₃N has 9 moles of C, 13 moles of H, 3 moles of O and 1 mol of N

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Use your experimentally determined value of ksp and show,by calculations, that ag2cro4 should precipitate when 5ml of 0.004m agn
Doss [256]
When the value of Ksp = 3.83 x 10^-11 (should be given - missing in your Q)

So, according to the balanced equation of the reaction:

and by using ICE table:

              Ag2CrO4(s)  → 2Ag+ (Aq) + CrO4^2-(aq)

initial                                     0                   0

change                              +2X                 +X

Equ                                       2X                   X

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so by substitution:

∴ 3.83 x 10^-11 = (2X)^2* X

3.83 x 10^-11 = 4 X^3

∴X = 2.1 x 10^-4 

∴[CrO42-] = X = 2.1 x 10^-4 M

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                  = 4.2 x 10^-4 M

when we comparing with the actual concentration of [Ag+] and [CrO42-]

when moles Ag+ = molarity * volume

                               = 0.004 m * 0.005L

                               = 2 x 10^-5 moles
[Ag+] = moles / total volume
     
          = 2 x 10^-5 / 0.01L

          = 0.002 M

moles CrO42- = molarity * volume

                         = 0.0024 m * 0.005 L

                         = 1.2 x 10^-5 mol

∴[CrO42-] = moles / total volume

                 = (1.2 x 10^-5)mol / 0.01 L 

                 = 0.0012 M

by comparing this values with the max concentration that is saturation in the solution 

and when the 2 values of ions concentration are >>> than the max values o the concentrations that are will be saturated.

∴ the excess will precipitate out       
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