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ira [324]
1 year ago
6

Does the pH increase or decrease, and does it do so to a large or small extent, with each of the following additions?(c) 5 drops

of 0.1 M NaOH to 100 mL of 0.5 M HCl
Chemistry
1 answer:
Umnica [9.8K]1 year ago
6 0

The pH decreases to a large or small extent with each of the given additions.

<h3>What is common name of NaOH?</h3>

The common name of NaOH is sodium hydroxide. Lye and caustic soda are other names for sodium hydroxide, an inorganic substance having the formula NaOH. It is a white, solid ionic substance made up of the cations sodium (Na+) and the anions hydroxide (OH). Sodium hydroxide is a chemical that manufacturers utilize to make things like soap, rayon, paper, explosives, colors, and petroleum products. Processing cotton fabrics, metal cleaning and processing, oxide coating, electroplating, and electrolytic extraction are further uses for sodium hydroxide. A caustic metallic base is sodium hydroxide (NaOH), sometimes referred to as lye or caustic soda. Caustic soda, an alkali, is commonly employed in a variety of sectors, primarily as a potent chemical base in the production of pulp and paper, textiles, drinking water, and detergents.

To learn more about sodium hydroxide, visit:

brainly.com/question/24010534

#SPJ4

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2) 2KClO3 --&gt; 2KCl + 3O2
aleksandrvk [35]

2 \text{ KClO}_3 \to 2 \text{ KCl}+3\text{ O}_2

a)

2 \text{ mols of KClO}_3 \equiv 3  \text{ mols of O}_2

19 \text{ mols of KClO}_3 \equiv 3\cdot 9,5  \text{ mols of O}_2

\boxed{19 \text{ mols of KClO}_3 \equiv 28,5  \text{ mols of O}_2}

b)

2 \text{ mols of KClO}_3 \equiv 2  \text{ mols of KCl}

62 \text{ mol of KClO}_3 \equiv 62  \text{ mol of KCl}

Using the atomic mass given in the periodic table:

62\cdot(39+35,5+16\cdot3) \text{ g of KClO}_3 \equiv 62  \text{ mol of KCl}

62\cdot122,5 \text{ g of KClO}_3 \equiv 62  \text{ mol of KCl}

7595 \text{ g of KClO}_3 \equiv 62  \text{ mol of KCl}

\boxed{7,595 \text{ kg of KClO}_3 \equiv 62  \text{ mol of KCl}}

c)

2 \text{ KCl}+3\text{ O}_2\to 2 \text{ KClO}_3

3 \text{ mols of O}_2 \equiv 2 \text{ mols of KCl}

Using the atomic mass given in the periodic table:

3\cdot(2\cdot 16) \text{ g of O}_2 \equiv 2\cdot(39+35,5)  \text{ g of KCl}

96\text{ g of O}_2 \equiv 149\text{ g of KCl}

\dfrac{39}{149}\cdot 96\text{ g of O}_2 \equiv \dfrac{39}{149}\cdot 149\text{ g of KCl}

\boxed{25,13\text{ g of O}_2 \equiv 39\text{ g of KCl}}

This result is an aproximation.

8 0
3 years ago
How many mg of salt are in a 2.78 kg bag of salt?
igomit [66]

Answer:

2,780,000mg

Explanation:

Using the Metric Staircase photo provided, you can calculate how many mg there are in 2.78 kg by simply moving the decimal point six places to the right, since the "Kilo" step takes six places to move to the "Milli" step.

2.78 kg

---------------

2 7 8 0 0 0 0 .

we can see that the decimal point is moved to the right six places.

Answer:

2,780,000mg

7 0
3 years ago
2a. What is the difference between weight and mass?
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1 year ago
A gas has a temperature of 14 oC and volume of 4.5 liters. If the temperature is raised to 29
kirza4 [7]

Answer:

The new volume of the gas is 4.74L

Explanation:

Data;

T1 = 14°C = (14 + 273.15)K = 287.15K

V1 = 4.5L

T2 = 29°C = (29 + 273.15)K = 302.15

V2 = ?

From Charles law,

The volume of a fixed mass of gas is directly proportional to its temperature provided that pressure remains constant.

Mathematically,

V = kT

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V1 / T1 = V2 / T2

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V2 = (V1 * T2) / T1

V2 = (4.5 * 302.15) / 287.15

V2 = 4.735L

V2 = 4.74L

The new volume of the gas is 4.74L

7 0
3 years ago
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