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Blababa [14]
3 years ago
12

Solid iron(II) sulfide reacts with aqueous hydrochloric acid HCl to produce hydrogen sulfide gas H2S and aqueous iron(II) chlori

de . Write a balanced chemical equation for this reaction.
Chemistry
1 answer:
Marina CMI [18]3 years ago
5 0

Answer:

<h2> 2 HCl(aq) + FeS(s) --->  FeCl_{2(aq) +H_{2}S(g)</h2>

Explanation:

Here translate the words into the atomic symbol:

HCl(aq) + FeS(s) →FeCl2(aq) + H2S(g)

calculation;  

Hydrogens (H); 1 on left, 2 on right

Chloride (Cl);  1 on left, 2 on right

Iron (Fe) ; 1 on left, 1 on right

Sulfur (s);  1 on left, 1 on right

Balancing ; So, need 1 more Hydrogen on the left and 1 more Chloride on the left.  The easiest way to do this is to put a 2 in front of HCl.  

<em>2 HCl(aq) + FeS(s) --->   </em>FeCl_{2(aq) +H_{2}S(g)

Now there are two hydrogens, two chlorides, one iron, and one sulfur on the left and the same on the right.

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8 0
2 years ago
What is the net charge of C
sashaice [31]

Explanation:

Sorry, I don't know, but I can tell you that when an atom, or a body, has the same amount of positive charges (protons) and negative charges (electrons), it is said to be electrically neutral. ... The net charge corresponds to the algebraic sum of all the charges that a body possesses.

5 0
2 years ago
Read 2 more answers
how many grams of calcium chloride can be prepared from 60.4 G of calcium oxide and 69.0 G of hydrochloric acid and a double dis
Ksenya-84 [330]
Balanced equation: 
<span>CaO + 2 HCl --> CaCl2 + H2O </span>
<span>Calculate moles of each reactant: </span>
<span>60.4 g CaO / 56.08 g/mol = 1.08 mol CaO </span>
<span>69.0 g HCl / 36.46 g/mol = 1.89 mol HCl </span>

<span>Identify the limiting reactant: </span>
<span>Moles CaO needed to react with all HCl: </span>
<span>1.89 mol HCl X (1 mol CaO / 2 mol HCl) = 0.946 mol CaO </span>
<span>Because you have more CaO than that available, HCl is the limiting reactant. </span>

<span>Calculate moles and mass CaCl2: </span>
<span>1.89 mol HCl X (1 mol CaCl2 / 2mol HCl) X 111.0 g/mol = 105 g CaCl2</span>
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Answer:

11111

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3 years ago
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Degger [83]

Answer: it is part of newtons second law. so the object to your question would accelerate

Explanation: newtons second law

 

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