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Blababa [14]
4 years ago
12

Solid iron(II) sulfide reacts with aqueous hydrochloric acid HCl to produce hydrogen sulfide gas H2S and aqueous iron(II) chlori

de . Write a balanced chemical equation for this reaction.
Chemistry
1 answer:
Marina CMI [18]4 years ago
5 0

Answer:

<h2> 2 HCl(aq) + FeS(s) --->  FeCl_{2(aq) +H_{2}S(g)</h2>

Explanation:

Here translate the words into the atomic symbol:

HCl(aq) + FeS(s) →FeCl2(aq) + H2S(g)

calculation;  

Hydrogens (H); 1 on left, 2 on right

Chloride (Cl);  1 on left, 2 on right

Iron (Fe) ; 1 on left, 1 on right

Sulfur (s);  1 on left, 1 on right

Balancing ; So, need 1 more Hydrogen on the left and 1 more Chloride on the left.  The easiest way to do this is to put a 2 in front of HCl.  

<em>2 HCl(aq) + FeS(s) --->   </em>FeCl_{2(aq) +H_{2}S(g)

Now there are two hydrogens, two chlorides, one iron, and one sulfur on the left and the same on the right.

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8 0
3 years ago
If the theoretical yield of a reaction is 0.110 g and the actual yield is 0.104 g , what is the percent yield?
Westkost [7]
Theoretical Yield is an Ideal yield with 100 % conversion of reactant to product. It is in fact a paper work.

While,

Actual Yield is the yield which is obtained experimentally. It is always less than theoretical yield because it is not possible to have 100% conversion of reactants into products. Even some amount of product is lost while handling it during the process.

Percentage Yield is Calculated as,

                    %age Yield  =  Actual Yield / Theoretical Yield × 100

Data Given:
                   Actual Yield  =  0.104 g

                   Theoretical Yield  =  0.110 g

Putting Values,

                    %age Yield  =  0.104 g / 0.110 g × 100

                    %age Yield  =  94.54 %
3 0
3 years ago
Round off each number to the indicated number of significant figures (sf)
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Answer:

The answer is B

Explanation:

3 0
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Answer:

6gkwkskekekkr

Explanation:

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A sample of an unidentified compound contains 29.84% sodium, 67.49% chromium, and 72.67% oxygen. What is the compound's empirica
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Explanation:

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