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Blababa [14]
4 years ago
12

Solid iron(II) sulfide reacts with aqueous hydrochloric acid HCl to produce hydrogen sulfide gas H2S and aqueous iron(II) chlori

de . Write a balanced chemical equation for this reaction.
Chemistry
1 answer:
Marina CMI [18]4 years ago
5 0

Answer:

<h2> 2 HCl(aq) + FeS(s) --->  FeCl_{2(aq) +H_{2}S(g)</h2>

Explanation:

Here translate the words into the atomic symbol:

HCl(aq) + FeS(s) →FeCl2(aq) + H2S(g)

calculation;  

Hydrogens (H); 1 on left, 2 on right

Chloride (Cl);  1 on left, 2 on right

Iron (Fe) ; 1 on left, 1 on right

Sulfur (s);  1 on left, 1 on right

Balancing ; So, need 1 more Hydrogen on the left and 1 more Chloride on the left.  The easiest way to do this is to put a 2 in front of HCl.  

<em>2 HCl(aq) + FeS(s) --->   </em>FeCl_{2(aq) +H_{2}S(g)

Now there are two hydrogens, two chlorides, one iron, and one sulfur on the left and the same on the right.

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The enthalpy of combustion of n-octane, C8H18, is –4.79 × 107 J/kg. What is the enthalpy of combustion expressed in kJ/g?
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<em></em>

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