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Shkiper50 [21]
4 years ago
6

Help me find X????? I'm not good with triangle at all so please help me as soon as you can. I have 9 weeks testing tomorrow and

idk how to do them

Mathematics
1 answer:
photoshop1234 [79]4 years ago
4 0
X=7.5 (d)
Since the 16 side is proportional to the 12 side, x is proportional to 10. 16/12 is 1.3333 so 10/1.333 is 7.5.
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Find the HCF of 96 and 108
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PLS ANSWER QUICK LOL
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(3j, 3k) and (3/j, 3k)

So if their x values have the same signs and their y values have the same signs, they are in the same quadrant.

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4 years ago
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What is the value of x in the equation 2.5 (6x-4h=10 +4(1.5 + 0.5x)
Komok [63]

Answer:

In this equation x is equal to h + 1

Step-by-step explanation:

To solve this, follow the order of operations for solving equations.

(6x-4h) = 10 + 4(1.5 + 0.5x) ----> Distribute the 4

(6x - 4h) = 10 - 6 + 2x ----> Simplify

6x - 4h = 4 + 2x ----> Subtract 4 from both sides

6x - 4h - 4 = 2x ----->Subtract 6x from both sides

-4h - 4 = -4x ----> Divide by -4

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3 0
3 years ago
A random sample of 20 recent weddings in a country yielded a mean wedding cost of $ 26,388.67. Assume that recent wedding costs
Makovka662 [10]

Answer:

a) 95% confidence interval for the mean​cost, μ​, of all recent weddings in this country = (22,550.95, 30,226.40)

.The​ 95% confidence interval is from $22,550.95 to $30,226.40.

b) For the interpretation of the result, option D is correct.

We can be​ 95% confident that the mean​ cost, μ​, of all recent weddings in this country is somewhere within the confidence interval.

c) Option B is correct.

The population mean may or may not lie in this​ interval, but we can be​ 95% confident that it does.

Step-by-step explanation:

Sample size = 20

Sample Mean = $26,388.67

Sample Standard deviation = $8200

Confidence Interval for the population mean is basically an interval of range of values where the true population mean can be found with a certain level of confidence.

Mathematically,

Confidence Interval = (Sample mean) ± (Margin of error)

Sample Mean = 26,388.67

Margin of Error is the width of the confidence interval about the mean.

It is given mathematically as,

Margin of Error = (Critical value) × (standard Error of the mean)

Critical value will be obtained using the t-distribution. This is because there is no information provided for the population mean and standard deviation.

To find the critical value from the t-tables, we first find the degree of freedom and the significance level.

Degree of freedom = df = n - 1 = 20 - 1 = 19.

Significance level for 95% confidence interval

(100% - 95%)/2 = 2.5% = 0.025

t (0.025, 19) = 2.086 (from the t-tables)

Standard error of the mean = σₓ = (σ/√n)

σ = standard deviation of the sample = 8200

n = sample size = 20

σₓ = (8200/√20) = 1833.6

99% Confidence Interval = (Sample mean) ± [(Critical value) × (standard Error of the mean)]

CI = 26,388.67 ± (2.093 × 1833.6)

CI = 26,388.67 ± 3,837.7248

99% CI = (22,550.9452, 30,226.3948)

99% Confidence interval = (22,550.95, 30,226.40)

a) 95% confidence interval for the mean​cost, μ​, of all recent weddings in this country = (22,550.95, 30,226.40)

.The​ 95% confidence interval is from $22,550.95 to $30,226.40.

b) The interpretation of the confidence interval obtained, just as explained above is that we can be​ 95% confident that the mean​ cost, μ​,of all recent weddings in this country is somewhere within the confidence interval

c) A further explanation would be that the population mean may or may not lie in this​ interval, but we can be​ 95% confident that it does.

Hope this Helps!!!

4 0
3 years ago
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