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Romashka [77]
3 years ago
5

Fluorine has an atomic number 9. It is in period 2 of the periodic table. The diagram shows the electron dot diagram of a fluori

ne atom. How many valence electrons are in an atom of fluorine? two seven nine seventeen
Chemistry
2 answers:
jek_recluse [69]3 years ago
6 0

Fluorine has C seven valence electrons.

Valence electrons are the electrons that are found on the outer shell of an atom that are capable of participating in chemical reactions. The easiest way to figure out how many valance electrons Fluorine has would be to look it up in a periodic table and notice that it a group 7 element and therefore has 7 valence electrons.

The other way to tell that Fluorine has 7 valence electrons is to notice that an element with an atomic number of 9 has 9 electrons. The electronic configuration of elements has the first 2 electrons go on the first shell or energy level 1s^2 , the leaving the next 7 to go to the second shell 2s^22p^5 which can take up to 8 electrons.

This means that Fluorine has 7 seven valence electrons.

jenyasd209 [6]3 years ago
3 0

The answer is B. 7  

Hope this helps! :)

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8 0
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2. The alcohol in "gasohol" burns according to the following equation.
Roman55 [17]

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7 0
3 years ago
How many moles of Al are necessary to form 23.6 g of AlBr₃ from this reaction: 2 Al(s) + 3 Br₂(l) → 2 AlBr₃(s) ?
Gnoma [55]

Answer:

0.088 mole of Al.

Explanation:

First, we shall determine the number of mole in 23.6 g of AlBr₃.

This is illustrated below:

Mass of AlBr₃ = 23.6 g

Molar Mass of AlBr₃ = 27 + 3(80) = 267 g/mol

Mole of AlBr₃ =.?

Mole = mass/Molar mass

Mole of AlBr₃ = 23.6 / 267

Mole of AlBr₃ = 0.088 mol

Next, we shall writing the balanced equation for the reaction.

This is given below:

2Al(s) + 3Br₂(l) → 2AlBr₃(s)

From the balanced equation above,

2 moles of Al reacted with 3 mole of Br₂ to 2 moles AlBr₃.

Finally, we shall determine the number of mole of Al needed for the reaction as follow:

From the balanced equation above,

2 moles of Al reacted to 2 moles AlBr₃.

Therefore, 0.088 mole of Al will also react to produce 0.088 mole of AlBr₃.

4 0
3 years ago
A reaction was performed in which 4.0 g of cyclohexanol was reacted with an acid catalyst to obtain 2.8 g of cyclohexene. calcul
ioda

Answer:

              %age Yield  =  85.36 %

Solution:

The Balance Chemical Reaction is as follow,

               C₆H₁₂O  +   Acid Catalyst    →    C₆H₁₀  +  Acid Catalyst + H₂O

According to Equation ,

              100 g (1 mole) C₆H₁₂O produces  =  82 g (1 moles) of C₆H₁₀

So,

                       4.0 g of C₆H₁₂O will produce  =  X g of C₆H₁₀

Solving for X,

                      X =  (4.0 g × 82 g) ÷ 100 g

                      X  =  3.28 g of C₆H₁₀   (Theoretical Yield)

As we know,

                     %age Yield  =  (Actual Yield ÷ Theoretical Yield) × 100

                     %age Yield  =  (2.8 g ÷ 3.28 g) × 100

                     %age Yield  =  85.36 %

5 0
3 years ago
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