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Nesterboy [21]
3 years ago
8

50 POINTSS !!!! HELP

Chemistry
1 answer:
Tanya [424]3 years ago
6 0
Do you have anymore information
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Which of the following would be classified as an acid to the Arrhenius definition
mixer [17]

Any substance that increases the concentration of H^+ in aqueous solutions is Arrhenius's acid.

<h3>What are Arrhenius acids?</h3>

Arrhenius define acids as substances with the chemical capacities to increase the concentration of hydrogen ion in aqueous solutions.

Thus, substances like HCl, HNO3, HBr, etc. would be considered an acid. This is because they ionize in aqueous solutions as follows:

HCl ---> H^+ + Cl^-

HNO_3 --- > H^+ + NO_3^-

HBr --- > H^+ + Br^-

More on Arrhenius acids can be found here: brainly.com/question/9936252

#SPJ1

4 0
2 years ago
Read 2 more answers
Please help does anyone know this// science!
Gwar [14]

Answer:

its A

Explanation:

The only one that makes sense

3 0
3 years ago
Scientists use tiltmeters to locate hidden faults. <br> true or false<br> answer: false
kari74 [83]
Hi, 
your answer would be false. But it seems you already knew that. 

I hoped I helped and if you need help you could always ask me :)

-Dawn
7 0
3 years ago
Read 2 more answers
When the concentrations of CH 3 Br and NaOH are both 0.100 M, the rate of the reaction is 0.0030 M/s. What is the rate of the re
mash [69]

Answer : The rate of the reaction if the concentration of CH_3Br is doubled is, 0.006 M/s

Explanation :

Rate law : It is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

The balanced equations will be:

CH_3Br+NaOH\rightarrow CH_3OH+NaBr

In this reaction, CH_3Br and NaOH are the reactants.

The rate law expression for the reaction is:

\text{Rate}=k[CH_3Br][NaOH]

As we are given that:

[CH_3Br] = concentration of CH_3Br = 0.100 M

[NaOH] = concentration of NaOH = 0.100 M

Rate = 0.0030 M/s

Now put all the given values in the above expression, we get:

0.0030M/s=k\times (0.100M)\times (0.100M)

k=0.3M^{-1}s^{-1}

Now we have to calculate the rate of the reaction if the concentration of CH_3Br is doubled.

\text{Rate}=k[CH_3Br][NaOH]

\text{Rate}=(0.3M^{-1}s^{-1})\times (2\times 0.100M)\times (0.100M)

\text{Rate}=0.006M/s

Thus, the rate of the reaction if the concentration of CH_3Br is doubled is, 0.006 M/s

3 0
4 years ago
The density of acetic acid is 1.05 g/mL. What is the volume of 327 g of acetic acid
Eva8 [605]

Answer:

311.43\ \text{mL}

Explanation:

\rho = Density of acetic acid = 1.05\ \text{g/mL}

m = Mass of acetic acid = 327\ \text{g}

V = Volume

Density is given by

\rho=\dfrac{m}{V}\\\Rightarrow V=\dfrac{m}{\rho}\\\Rightarrow V=\dfrac{327}{1.05}\\\Rightarrow V=311.43\ \text{mL}

The volume of acetic acid is 311.43\ \text{mL}.

8 0
3 years ago
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