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dedylja [7]
3 years ago
13

How is the molecule of a substance formed?

Chemistry
2 answers:
ollegr [7]3 years ago
7 0

Answer:

A molecule exists when two or more atoms join together by forming chemical bonds. ... When atoms of at least two different elements come together to form chemical bonds, these molecules can be called compounds. Sodium chloride (NaCl) is a classic example of an ionic compound, or compound formed by ionic bonds.

Explanation:

KatRina [158]3 years ago
6 0

A molecule can be formed by two or more Atoms joining together to form Chemical bonds

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The chemical agent or hazardous material that interferes with the body's ability to transfer oxygen to the cells is:
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Phosgene its a my friend used in the war
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2 years ago
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Convert the following to scientific notation 24,212,000
UNO [17]
2.4212 X 10^ 7
How I at least figure this problem out is I take a pencil and start on the right side of the 0 and make a loop to the left for each number and count until I get to the first two numbers that are between 1-9 when reading from left to right. This is where you put the decimal point. Some teachers rather you keep the 0's there, while others prefer one to get rid of them. Anyways with that new decimal number, you multiply the decimal by ten to what ever number you counted, which was 7.
5 0
3 years ago
How many moles are in a 12.0 g sample of NiC12
Nady [450]

Answer:

0.17 moles

Explanation:

In the elements of the periodic table, the atomic mass = molar mass. <u>Ex:</u> Atomic mass of Carbon is 12.01 amu which means molar mass of Carbon is also 12.01g/mol.

In order to find the # of moles in a 12 g sample of NiC-12, we will need to multiply the number of each atom by its molar mass and then add the masses of both Nickel and C-12 found in the periodic table:

  • Molar Mass of Ni (Nickel): 58.69 g/mol
  • Molar Mass of C (Carbon): 12.01 g/mol

Since there's just one atom of both Carbon and Nickel, we just add up the masses to find the molar mass of the whole compound of NiC-12.

  • 58.69 g/mol of Nickel + 12.01 g/mol of Carbon = 70.7 g/mol of NiC-12

There's 12g of NiC-12, which is less than the molar mass of NiC-12, so the number of moles should be less than 1. In order to find the # of moles in NiC-12, we need to do some dimensional analysis:

  • 12g NiC-12 (1 mol of NiC-12/70.7g NiC-12) = 0.17 mol of NiC-12
  • The grams cancel, leaving us with moles of NiC-12, so the answer is 0.17 moles of NiC-12 in a 12 g sample.

<em>P.S. C-12 or C12 just means that the Carbon atom has an atomic mass of 12amu and a molar mass of 12g/mol, or just regular carbon.</em>

5 0
3 years ago
Freon−12 (CF2Cl2), widely used as a refrigerant and aerosol propellant, is a dangerous air pollutant. In the troposphere, it tra
nevsk [136]

Answer:

141g of CCl₄

Explanation:

First, we have to write the balanced equation.

CCl₄(g) + 2 HF(g) ⇄ CF₂Cl₂(g) + 2 HCl(g)

We can calculate how many moles of CF₂Cl₂ using the ideal gas equation.

V = 14.9 dm³ = 14.9 L

T = 21°C + 273.15 = 294.15 K

P = 1.48 atm

R = 0.08206 atm.L/mol.K

P.V=n.R.T\\n=\frac{P.V}{R.T} =\frac{1.48atm.14.9L}{0.08206\frac{atm.L}{mol.K}.294.15K }=0.914mol

We can use proportions to find the mass of CCl₄ required to obtain 0.914 moles of CF₂Cl₂. According to the balanced equation, 1 mol of CF₂Cl₂ is produced when 1 mol of CCl₄ reacts. And the molar mass of CCl₄ is 154 g/mol.

0.914molCF_{2}Cl_{2}.\frac{1molCCl_{4}}{1molCF_{2}Cl_{2}} .\frac{154gCCl_{4}}{1molCCl_{4}} =141gCCl_{4}

7 0
3 years ago
g Five calcite, CaCO3 (MW 100.085 g/mol), samples of equal mass have a total mass of 12.3±0.1 g. What is the absolute uncertaint
diamong [38]

Answer:

The value  is   L  =  0.985 \pm 0.00801 \  g

Explanation:

From the question we are told that

  The  molar mass of CaCO_3 is  MW  =  100.085 \  g/mol

   The  total mass is  m_g  = 12.3 \ g

   The uncertainty of the total mass is \Delta g  = 0.1

Generally the molar weight of calcium is M_c  =  40 g/mol

 The percentage of calcium in calcite is mathematically represented as

          C =  \frac{40.07}{100.085} * 100

          C =  40.03 \%

Generally the mass of each sample is mathematically represented as

     m=  \frac{m_g}{5}

     m=  \frac{12.3}{5}

     m= 2.46 \  g

Generally mass of calcium present in a single sample is mathematically represented as

        m_c = 2.46 *  \frac{40.04}{100}

       m_c = 0.985 \  g

The  uncertainty of  mass of a single sample is mathematically represented as

      k  =  \frac{\Delta g }{5}

        k  =  \frac{0.1 }{5}

       k  =  0.02\  g

The  uncertainty of  mass of calcium in a single sample is mathematically represent

         G  =  \frac{0.02 *  40.04}{ 100}

          G  =  0.00801 \  g

Generally the average mass of calcium in each sample is  

          L  =  0.985 \pm 0.00801

6 0
3 years ago
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