Answer:
use the equation Mass= RFM*Moles
Explanation:
use your periodic table
and create a little table
<span>d. A catalyst will be used up in the reaction is wrong,
amount of catalyst should not change</span>
Answer:
M = 20.5 g/mol
Explanation:
Given data:
Volume of gas = 1.20 L
Mass of gas = 1.10 g
Temperature and pressure = standard
Solution:
First of all we will calculate the density.
Formula:
d = mass/ volume
d = 1.10 g/ 1.20 L
d = 0.92 g/L
Now we will calculate the molar mass.
d = PM/RT
0.92 g/L = 1 atm × M / 0.0821 atm.L/mol.K ×273.15 K
M = 0.92 g/L × 0.0821 atm.L/mol.K ×273.15 K / 1 atm
M = 20.5 g/mol
The solution has a concentration 20 mgr in each mL of the final solution.
To solve this problem, we need to know about concentration. The concentration formula can be defined as how much the mass per unit volume is. It can be written as
M = m/V
where M is concentration, m is mass of solute, V is the total volume of solution.
From the text we know that :
m = 10g
vsolvent = 45mL
vsolute = 5 mL
find the total volume (V)
V = vsolvent + vsolute
V = 45 + 5
V = 50mL
Then, find the concentration
M = m/V
M = 10gr / 50 mL
M = 1000 mgr / 50mL
M = 20 mgr / mL
Hence, the solution has a concentration 20 mgr in each mL of the final solution.
Find more on concentration at: brainly.com/question/17206790
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