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3 years ago

Energy needs, in total kilocalories per day, are greater during _____________ than any other time of life.

Physics

2 answers:

frutty [35]3 years ago

6 0

Answer:

b. adolescence

Explanation:

malfutka [58]3 years ago

5 0

Energy needs, in total kilocalories per day, are greater during adolescence than any other time of life. The correct option among all the options that are given in the question is the second option or option "b". Only during the time of pregnancy will a girl require more kilocalories per day than during the time of adolescence.

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A car travels across Texas m miles at the rate of t miles per hour. How many hours does the trip take??

Marianna [84]

Answer: The trip takes $\frac{m}{t}hours$

Explanation:

Velocity $V$ is the variation of the position of a body (distance traveled $d$ ) with time $T$ :

$V=\frac{d}{T}$

In this case, the car travels a distance $d=m miles$ at a velocity $V=t \frac{miles}{hour}$ and we need to find the time it takes the trip.

Isolating $T$ :

$T=\frac{d}{V}=\frac{m miles}{t \frac{miles}{hour}}$

Finally:

$T=\frac{m}{t}hours$

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3 years ago

How is it possible to get three precise but inaccurate measurements of the same volume of water

Lubov Fominskaja [6]

The inaccurate measurements must be similar to the other two measurements (ex; 590, 589, 599), but different from the actual volume of water. (Ex; the actual volume is let say.. 100, but you measured 50, 49, 40)

8 0

2 years ago

3. A sprinter leaves the starting blocks with an acceleration of 4.5 m/s2. What is the

UkoKoshka [18]

Hi there! :)

$\large\boxed{v_{f} = 18 m/s}$

Use the following kinematic equation to solve for the final velocity:

$v_{f} = v_{i} + at$

In this instance, the runner started from rest, so the initial velocity is 0 m/s. We can rewrite the equation as:

$v_{f} = at$

Plug in the given acceleration and time:

$v_{f} = 4.5 * 4 = 18 m/s$

5 0

3 years ago

g a small smetal sphere, carrying a net charge is held stationarry. what is the speed are 0.4 m apart

Veseljchak [2.6K]

Answer:

The speed of q₂ is $4\sqrt{10}\ m/s$

Explanation:

Given that,

Distance = 0.4 m apart

Suppose, A small metal sphere, carrying a net charge q₁ = −2μC, is held in a stationary position by insulating supports. A second small metal sphere, with a net charge of q₂ = −8μC and mass 1.50g, is projected toward q₁. When the two spheres are 0.800m apart, q₂ is moving toward q₁ with speed 20m/s.

We need to calculate the speed of q₂

Using conservation of energy

$E_{i}=E_{f}$